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LenaWriter [7]
4 years ago
9

Suppose the ring rotates once every 3.80 s . if a rider's mass is 59.0 kg , with how much force does the ring push on her at the

top of the ride?
Physics
1 answer:
galina1969 [7]4 years ago
5 0
F=ma so, do 3.80s x 59 KG which will give you your answer, hope this helps <3
You might be interested in
Mr. Beall paddles his canoe at 8.0 m/s North in a river that flows at 6.0 m/s to the South. What is the magnitude and direction
kifflom [539]

Answer:

2 /s north

Explanation:

Given that,

Velocity due North is 8 m/s and due south is 6 m/s

We need to find the magnitude and the direction of the resulting velocity.

Let North is positive and South is negative. When two velocities are in opposite direction, they adds up. So,

v=8+(-6)\\\\v=2\ m/s

It is positive. So, it is in North direction.

3 0
3 years ago
A boat is cruising in a straight line at a constant speed of 2.6 m/s when it is shifted into neutral. after coasting 11.0 m the
yawa3891 [41]

We know that rate of acceleration is constant, which means change of velocity is constant (velocity changes in a linear way). The boat coasted for 11 meters and its speed decreased by 1 m/s. Since deceleration is constant, we can find out how much time the boat spent coasting by dividing 11 meters (distance traveled) by average speed ((2.6+1.6)/2), which gives us 11 /2.1 = 5.238 seconds. The rate of deceleration is change in velocity divided by time. -1 m/s divided by 5.238 seconds = -.19m/s/s.

7 0
4 years ago
Help on this physics question
fredd [130]

By using the equations for <em>parabolic</em> motion, we proceed to present the answers for the paragraph seen in the picture: a) t ≈ 0.553 s, b) s = 2.212 m, c) s = 11.060 m.

<h3>How to analyze a system on parabolic motion</h3>

A system is on <em>parabolic</em> motion if such system can be represented as a particle, that is, a system whose geometry is negligible, and its motion is a combination of <em>horizontal</em> movement at <em>constant</em> velocity and <em>vertical</em> <em>uniformly accelerated</em> movement due to gravity and all <em>viscous</em> and <em>rotational</em> effects are negligible.

The time required for the droplet to reach the ground is:

1.5 m = (1 / 2) · (9.807 m / s²) · t²

t = √[2 · (1.5 m) / (9.807 m / s²)]

t ≈ 0.553 s

And the <em>horizontal</em> distance traveled by the droplet is:

s = (4 m / s) · (0.553 s)

s = 2.212 m

Now, we apply the same procedure for the case of sneezing person:

1.5 m = (1 / 2) · (9.807 m / s²) · t²

t = √[2 · (1.5 m) / (9.807 m / s²)]

t ≈ 0.553 s

s = (20 m / s) · (0.553 s)

s = 11.060 m

To learn more on parabolic motion: brainly.com/question/16992646

#SPJ1

8 0
2 years ago
Mrs. Walker has on new shoes! When she walks down the waxed hall floors she slips and slides. What could Mrs. Walker do to help
givi [52]
She could choose to wear shoes designed to have more friction on the bottom, so she won’t slip as easily... (or she could get like a walker or something to hold onto if she really wanted to show off her new shoes)
Hope this helps x
3 0
3 years ago
Express the length of a marathon run of<br> 26 mi 385 yd in meters.<br> Answer in units of m.
hjlf

Answer:

1 mi = 5280 ft  * 12 in/ft = 63360 in

A convenient conversion factor (to remember) is 1 m = 39.37 in

63360 in / (39.37 in / m) = 1609.3 m

26 mi + 285 m = 26 * 1609.3 + 385 = 42,228 m

6 0
3 years ago
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