Suppose the ring rotates once every 3.80 s . if a rider's mass is 59.0 kg , with how much force does the ring push on her at the
1 answer:
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Answer: 0.5
Explanation:
The modulus of elasticity (called <em>"alargamiento unitario"</em> in spanish) of a spring is given by the following formula:
Where:
is the original length of the spring
is the elongation of the spring, being
the length of the spring after a force is applied to it.
Then:
