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guapka [62]
3 years ago
14

PLEASE ASAP ILL GIVE BRAINLIEST.

Physics
1 answer:
Fiesta28 [93]3 years ago
5 0
Acceleration no longer exist as the car stops.
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Compare and contrast sound waves and electromagnetic waves. Any bs answers will be reported. Please hurry!!!
Trava [24]

Answer:

They are both forms of energy.  One has to do with hearing and the other a little bit of light.

Explanation:

3 0
2 years ago
Which is the fundamental law of energy?
Mkey [24]
Energy cannot be created nor be destroyed
6 0
3 years ago
Read 2 more answers
A projectile rolls off a cliff with a velocity of 40 m/s. The cliff is 60 meters high.
masya89 [10]

Answer:

1) t = 3.45 s, 2)  x = 138 m, 3) v_{y} = -33.81 m /s, 4) v = 52.37 m / s ,

5) θ = -40.2º

Explanation:

This is a projectile exercise, as they indicate that the projectile rolls down the cliff, it goes with a horizontal speed when leaving the cliff, therefore the speed is v₀ₓ = 40 m / s.

1) Let's calculate the time that Taardaen reaches the bottom, we place the reference system at the bottom of the cliff

      y = y₀ + v_{oy} t - ½ g t²

When leaving the cliff the speed is horizontal  v_{oy}= 0 and at the bottom of the cliff y = 0

      0 = y₀ - ½ g t2

      t = √ 2y₀ / g

      t = √ (2 60 / 9.8)

      t = 3.45 s

2) The horizontal distance traveled

     x = v₀ₓ t

     x = 40 3.45

     x = 138 m

3) The vertical velocity at the point of impact

     v_{y} = I go - g t

     v_{y} = 0 - 9.8 3.45

     v_{y} = -33.81 m /s

the negative sign indicates that the speed is down

4) the resulting velocity at this point

   v = √ (vₓ² + v_{y}²)

   v = √ (40² + 33.8²)

   v = 52.37 m / s

5) angle of impact

    tan θ = v_{y} / vx

    θ = tan⁻¹ v_{y} / vx

    θ = tan⁻¹ (-33.81 / 40)

    θ = -40.2º

6) sin (-40.2) = -0.6455

7) tan (-40.2) = -0.845

8) when the projectile falls down the cliff, the horizontal speed remains constant and the vertical speed increases, therefore the resulting speed has a direction given by the angle that is measured clockwise from the x axis

6 0
3 years ago
A 100 kg box is hanging from two strings. String #1 pulls up and left, making an angle of 80o with the horizontal on the left, a
frutty [35]

Answer:296.76 N

Explanation:

Given

mass of box m=100 kg

Let T_1 be the Tension in left side and T_2 be the Tension in the right side

From diagram

T_1\cos 80=T_2\cos 65

T_1=T_2\cdot \frac{\cos 65}{\cos 80}

and

T_1\sin 80+T_2\sin 65=100\cdot g

T_2\left [ \tan 80\cdot \cos 65+\sin 65\right ]=100\cdot g

T_2=\frac{100\cdot g}{\left [ \tan 80\cdot \cos 65+\sin 65\right ]}

T_2=\frac{980}{3.3023}=296.76 N

                       

3 0
3 years ago
The gravitational force between two objects is most affected by their
Oxana [17]

Answer:  mass and distance

Explanation:

5 0
3 years ago
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