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Ray Of Light [21]
3 years ago
8

PLEASE ANSWER ASAP

Physics
1 answer:
Sedbober [7]3 years ago
3 0

Answer:

B.

Explanation:

The water collects in the ocean; it is then evaporated by the sun. After evaporation the water turns into water vapor, it then condenses to form clouds.

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List two factors that compression force depends on ​
Anna [14]

The magnitude (size or numerical value) and the direction.

Hope this helps!!! :)

6 0
3 years ago
Use the graph above to determine the change in speed of the object between 20 and 30 seconds?
allsm [11]

Answer:

6 m/s

Explanation:

To determine the change in speed of the object, we just need to determine its speed at t = 30 s and at t = 20 s, and then calculate the difference.

The speed at t = 30 is:

v = 6 m/s

While the speed at t = 20 s is:

u = 0

Therefore, the change in speed is:

\Delta v = v-u=6-0 = 6 m/s

4 0
3 years ago
Read 2 more answers
A crate resting on a horizontal floor (\muμs = 0.61, \muμk = 0.3 ) has a horizontal force F = 49 Newtons applied to the right. T
Darya [45]

Answer:

a = 7.80 m/s²

Explanation:

given,

μs = 0.61

μk = 0.3

F = 49 N

we know,

F = μs m g

m = \dfrac{F}{\mu_s\ g}

m = \dfrac{49}{0.61 \times 9.81}

m = 8.19\ kg

now when the block start moving

F - F_k = F_{net}

F - F_k = ma

a = \dfrac{F}{m}-\dfrac{F_k}{m}

a = \dfrac{F}{m}-\dfrac{\mu_k m g}{m}

a = \dfrac{88}{8.19}-0.3\times 9.8

a = 7.80 m/s²

3 0
4 years ago
If an object that weighs 20 N is lifted from the ground to a
Radda [10]

Answer:

false 20 n x 0.32 m = 6.4 J

3 0
4 years ago
A magnetic field of 37.2 t has been achieved at the mit francis bitter national magnetic laboratory. Find the current needed to
jeka57 [31]

Answer:

Here is the complete question:

https://www.chegg.com/homework-help/questions-and-answers/magnetic-field-372-t-achieved-mit-francis-bitter-national-magnetic-laboratory-find-current-q900632

a) Current for long straight wire  =3.7\ MA

b) Current at the center of the circular coil =2.48\times 10^{5}\ A

c) Current near the center of a solenoid 236.8\ A

Explanation:

⇒ Magnetic Field due to long straight wire is given by (B),where B=\frac{\mu\times I}{2\pi(r) },so\ I=\frac{B\ 2\pi(r)}{\mu}

\mu=4\pi \times 10^{-7}\ \frac{henry}{m}

Plugging the values,

Conversion 1\times 10^6 A = 1\ MA,and 2cm=\frac{2}{100}=0.02\ m

I=\frac{37.2\times \ 2\pi(0.02)}{4\ \pi \times (10^{-7})}=3.7\ MA

⇒Magnetic Field at the center due to circular coil (at center) is given by,B=\frac{\mu\times I (N)}{2(a)}

So I= \frac{2B(a)}{\mu\ N} = \frac{2\times 37.2\times 0.42}{4\pi\times 10^{-7}\times 100}=2.48\time 10{^5}\ A

⇒Magnetic field due to the long solenoid,B=\mu\ nI=\mu (\frac{N}{l})I

Then I=\frac{B}{\mu(\frac{N}{L})} \approx 236.8\A  

So the value of current are  3.7 MA,2.48\times 10^{5} A and 236.8\ A respectively.

8 0
3 years ago
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