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Tomtit [17]
2 years ago
6

27). How many feet per second is a wave going if it travels a distance of one mile in 7.35 seconds?

Chemistry
2 answers:
Tems11 [23]2 years ago
8 0

Answer:How many feet per second is a wave going if it travels a distance of one mile in 7.35 seconds? 9 feet loong

Explanation:

How many feet per second is a wave going if it travels a distance of one mile in 7.35 seconds? I be

Inessa [10]2 years ago
6 0

The speed of the wave would be 718.21 feet /second if a wave going if it travels a distance of one mile in 7.35 seconds.

<h3>What is speed?</h3>

The total distance covered by any object per unit of time is known as speed. It depends only on the magnitude of the moving object.

As given in the problem we have to find out how many feet per second is a wave going if it travels a distance of one mile in 7.35 seconds.

1 mile = 1609 meters

1 meters = 3.28084 feets

1609 meters = 1609 ×3.28084 feets

                     = 5278.87 feets

As given if the wave travels a distance of one mile in 7.35 seconds.

then the wave would travel at 5278.87 feet in 7.35 seconds.

speed of the wave = 5278.87 /7.35

                               = 718.21 feet /second

Thus, the speed of the wave would be 718.21 feet /second

To learn more about speed from here, refer to the link;

brainly.com/question/7359669

#SPJ2

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How many moles of oxygen are in 1 mole of fe(no3)3?
Naddika [18.5K]
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1 mole Fe(NO3)3 * (3 moles NO3)/(1 mole Fe(NO3)3) = 3 moles NO3
3 moles NO3 * (3 moles Oxygen)/(1 mole NO3) = 9 moles Oxygen
9 moles of Oxygen in one mole Fe(NO3)3
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3 years ago
Write a procedure for "how to crack an egg" in cooking. You must have at least 3 steps. The format of your procedure is more imp
Nataly_w [17]

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

Here's the procedure to Crack an egg ~

Step 1 ~

  • Hold the egg in your hand and tap it on a firm surface

Step 2 ~

  • Gently pull the shells apart

Step 3 ~

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6 0
2 years ago
How many moles of water were lost if the amount of water lost was 0.456 grams? Do not include units and assume three significant
nika2105 [10]
<h3>Answer:</h3>

0.0253 mol H₂O

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 0.456 g H₂O (water)

<u>Step 2: Identify Conversions</u>

[PT] Molar Mass of H - 1.01 g/mol

[PT] Molar Mass of O - 16.00 g/mol

Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                     \displaystyle 0.456 \ g \ H_2O(\frac{1 \ mol \ H_2O}{18.02 \ g \ H_2O})
  2. [DA] Multiply/Divide [Cancel out units]:                                                          \displaystyle 0.025305 \ mol \ H_2O

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

0.025305 mol H₂O ≈ 0.0253 mol H₂O

3 0
2 years ago
A gas mixture with a total pressure of 745 mmHg contains each of the following gases at the indicated partial pressures: CO2, 24
Setler79 [48]

<u>Answer:</u>

<u>For Part A:</u> The partial pressure of Helium is 218 mmHg.

<u>For Part B:</u> The mass of helium gas is 0.504 g.

<u>Explanation:</u>

  • <u>For Part A:</u>

We are given:

p_{CO_2}=245mmHg\\p_Ar}=119mmHg\\p_{O_2}=163mmHg\\P=745mmHg

To calculate the partial pressure of helium, we use the formula:

P=p_{CO_2}+p_{Ar}+p_{O_2}+p_{He}

Putting values in above equation, we get:

745=245+119+163+p_{He}\\p_{He}=218mmHg

Hence, the partial pressure of Helium is 218 mmHg.

  • <u>For Part B:</u>

To calculate the mass of helium gas, we use the equation given by ideal gas:

PV = nRT

or,

PV=\frac{m}{M}RT

where,

P = Pressure of helium gas = 218 mmHg

V = Volume of the helium gas = 10.2 L

m = Mass of helium gas = ? g

M = Molar mass of helium gas = 4 g/mol

R = Gas constant = 62.3637\text{ L.mmHg }mol^{-1}K^{-1}

T = Temperature of helium gas = 283 K

Putting values in above equation, we get:

218mmHg\times 10.2L=\frac{m}{4g/mol}\times 62.3637\text{ L.mmHg }mol^{-1}K^{-1}\times 283K\\\\m=0.504g

Hence, the mass of helium gas is 0.504 g.

6 0
3 years ago
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