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4 years ago

8

What is the average atomic mass!?

1 answer:

Agata [3.3K]4 years ago

6 0

Answer:

he average atomic mass of an element is the sum of the masses of its isotopes, each multiplied by its natural abundance

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The activation energy for a(n) _____ is quite large and usually takes extra energy from the environment, it is normally not a na

soldi70 [24.7K]

<span>Endothermic Reaction. This reaction or process absorbs energy from its surroundings, mostly, but will not always be, in form of heat. A reaction that requires the input of energy that breaks a bond will always be endothermic. Best examples of endothermic reaction are: 1) melting cubes; 2) evaporating of liquid; 3) melting solid salts, etc.</span>

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3 years ago

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Find the cell potential for a system whose ∆G = +55 kJ and 3 moles of electrons are exchanged.

rosijanka [135]

Answer:- cell potential = -0.19 volts

Solution:- The equation that shows the connection between $\Delta G$ and cell potential, E is written as:

$\Delta G=-nFE$

in this equation, n stands for moles of electrons, E stands for cell potential and F stands for faraday constant and it's value is $\frac{96485C}{mol}$ .

It asks to calculate the value of E, so let's rearrange the equation:

$E=-\frac{\Delta G}{nF}$

Let's plug in the values in it:

$E=-\frac{55kJ}{3mol*96485C.mol^-}$

$E=-\frac{0.00019kJ}{C}$

since, $\frac{1kJ}{C}=1000V$

Where C stands for coulombs and V stands for volts.

So, $E=-\frac{0.00019kJ}{C}(\frac{1000V}{\frac{1kJ}{C}})$

E = -0.19 V

So, the cell potential is -0.19 volts.

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3 years ago

Nitrogen and oxygen do not react appreciably at room temperature, as illustrated by our atmosphere. But at high temperatures, th

Gre4nikov [31]

Answer : The equilibrium concentration of NO is, 0.0092 M.

Solution :

First we have to calculate the concentration of NO.

$\text{Concentration of NO}=\frac{\text{Moles of }NO}{\text{Volume of solution}}=\frac{0.3152mol}{2.0L}=0.1576M$

The given equilibrium reaction is,

$N_2(g)+O_2(g)\rightleftharpoons 2NO(g)$

Initially conc. 0 0 0.1576

At eqm. (x) (x) (0.1576-2x)

The expression of $K_c$ will be,

$K_c=\frac{[NO]^2}{[N_2][O_2]}$

$0.0153=\frac{(0.1576-2x)^2}{(x)\times (x)}$

By solving the term, we get:

$x=0.0742,0.0839$

Neglecting the 0.0839 value of x because it can not be more than initial value.

Thus, the value of 'x' will be, 0.0742 M

Now we have to calculate the equilibrium concentration of NO.

Equilibrium concentration of NO = (0.1576-2x) = [0.1576-2(0.0742)] = 0.0092 M

Therefore, the equilibrium concentration of NO is, 0.0092 M.

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4 years ago

Check all substances that are excreted in humans.<br> 1.carbon dioxide<br> 2.urine<br> 3.salvia

Tatiana [17]

carbon dioxide and urine

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3 years ago

Metals are______ because light reflects off the electrons.

elena55 [62]

Metals are -shiny- because light reflects off the electrons.

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3 years ago

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