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kirill115 [55]
3 years ago
7

The period of a satellite in a circular orbit as the distance from the central object increases.

Physics
2 answers:
vovangra [49]3 years ago
5 0

Answer:

Increases

Explanation:

The period of a satellite in a circular orbit increases as the distance from the central object increases. It makes the most sense. Correct on Edge!

kow [346]3 years ago
4 0

Answer:

increases

Explanation:

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Statement A: Area of a rectangle with measured length = 2.536 mm and width = 1.4 mm.
pochemuha

Explanation:

Formula for calculating the area of a  rectangle A = Length *width

For statement A;

Given area of a rectangle with measured length = 2.536 mm and width = 1.4 mm.

Area of the rectangle = 2.536mm * 1.4mm

Area of the rectangle = 3.5504mm²

The rule of significant figures states that we should always convert the answer to the least number of significant figure amount the given value in question. Since 1.4mm has 2 significant figure, hence we will convert our answer to 2 significant figure.

Area of the rectangle = 3.6mm² (to 2sf)

For statement B;

Given area of a rectangle with measured length = 2.536 mm and width = 1.41 mm.

Area of the rectangle = 2.536mm * 1.41mm

Area of the rectangle = 3.57576mm²

Similarly, Since 1.41mm has 3 significant figure compare to 2.536 that has 4sf, hence we will convert our answer to 3 significant figure.

Area of the rectangle = 3.58mm² (to 3sf)

Based on the conversion, it can be seen that 3.6mm²  is greater than 3.58mm², hence the area of rectangle in statement A is greater than the area of the rectangle in statement B.

7 0
3 years ago
Please help me<br> gqvebqubgk yfawcyvgkbuh
Sergeu [11.5K]

Answer:CCCCCCCCCCCCCCCCC

Explanation:CCCCCCCCCCCCC

4 0
3 years ago
Read 2 more answers
Two wires each carry 10.0 A of current (in opposite directions) and are 2.50 mm apart. What is the magnetic field 37.0 cm away a
lyudmila [28]

Answer:

see answer below

Explanation:

Before we do any kind of calculation, we need to convert the proper units of the exercise. All the units of distance must be in meters, so, let's change distance of the wire, and the magnetic field to meters:

Separation between the wires are 2.5 mm:

2.5 mm * (1 m / 1000 mm) = 0.0025 m

The distance of P from the bottom of the wires is 37 cm:

37 cm * (1 m/100 cm) = 0.37 m

The distance of P from the top of the wires is just the sum of the two distances:

R = 0.37 + 0.0025 = 0.3725 m

Now that we have the distance, we can determine the magnetic field, using the following expression:

B = B(bottom) - B(top)   or just B₂ - B₁

And B = μ₀ I / 2πR

Replacing in the above expression we have:

B = μ₀ I / 2π ( 1/R₂ - 1/R₁)

Now we can determine the magnetic field:

B = (4πx10⁻⁷ * 10 / 2π) (1/0.37 - 1/0.3725)

<h2>B = 3.63x10⁻⁸ T</h2><h2></h2>

Which means that the magnetic field is out of the page.

Hope this helps

4 0
3 years ago
Which object will have the most potential energy?
Svetradugi [14.3K]

Answer:  the most potential energy ==  5 kg book, 2 m from the ground= 98 Joules

Explanation:

potential energy = m g h

m = mass

g = acceleration due gravity  = 9.8 m/s²

h = distance above  ground

1.  Pe₁ = 1 kg x 2 m x g  = 2 g

2. Pe₂ = 5 kg x 2 m x g = 10 g = 10 kg m x 9,8 m/s² = 98 Joules

3. Pe₃ = 1 kg x 0,5 m x g = 0,5 g

4. Pe₄ = 5 kg x 0.5 m x g = 2,5 g  

10 > 2,5 > 2 >0,5

5 0
3 years ago
A meteoroid is moving towards a planet. It has mass m = 0.78×109 kg and speed v1 = 4.1×107 m/s at distance R1 = 2.8×107 m from t
wariber [46]

Answer:

PE=81.755\, J

Explanation:

Given that:

  • mass of meteoroid, m=7.8\times 10^8 \,kg
  • radial distance from the center of the planet, R= 2.8\times 10^7 m
  • mass of the planet, M=4.4\times 10^{25}\, kg

<u>For gravitational potential energy we have:</u>

PE=G\frac{M.m}{R}

substituting the respective values:

PE=6.67\times 10^{-11}\times \frac{4.4\times 10^{25}\times 7.8\times 10^8}{2.8\times 10^7}

PE=81.755\, J

5 0
3 years ago
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