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3 years ago

How do you think density plays a role in the atmosphere?

1 answer:

4 0

Answer:
Also, gases like air are easily compressed. The weight of all the air above a given point in the atmosphere squeezes air molecules closer together. This causes the density to increase. The more air above a level (and hence the more weight of air above a level), the greater the compression.

Step By Step Explanation:

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Differences between <br>hor<br>rse<br>and horse

kenny6666 [7]

The proper difference between hor Rse and horse is both shows the same thing that is the horse

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3 years ago

Read 2 more answers

What is the disadvantage of the parallax method, especially for studying distant parts of the Galaxy?

Katena32 [7]

Answer and Explanation:

Parallax method is used for finding the distance of objects in space there are two types of parallax method that is stellar parallax and trigonometric parallax.The disadvantage of using parallax method is that it can can not reach so far in the Galaxy due to this reason parallax method is generally not used for measuring distance in galaxy.

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3 years ago

on june 21 some earth locations have 24 hours of daylight these locations are all between the latitudes of

andrew-mc [135]

66° N and 90° N

the area of the artic circle in the northern hemisphere

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3 years ago

A large truck is moving 22.0 m/s. If it’s momentum is 125,000 kg • m/s, what is the trucks mass

strojnjashka [21]

Answer:

p = mv

m = p/v = 125000/22 = 5682 kg

Explanation:

Direct application of the momentum equation

p = mv

where,

p: momentum

m: mass

v: object velocity

steps:

-------

1) check for units consistency ( SI or Imperial)

2) separate the variable you are looking for.

3) DONE! :DD

6 0

3 years ago

A 6.72 particle moves through a region of space where an electric field of magnitude 1270 N/C points in the positive direction,

Romashka [77]

Answer:

$v_{y} = -104 m/s$

Explanation:

Using:

Force = electric field * charge

$F=e*q$

Force = magnitude of charge * velocity * magnetic field * sin tither

$F_{x2}= |q|*v*B*sin \alpha$

Force on particle due to electric field:

$F_{x1}= E*q = (1270N/C)*(-6.72*10^{-6} ) = -8.53*10^{-3}$

Force on particle due to magnetic field:

$F_{x2}= |q|*v*B*sin \alpha = (6.72*10^{-6} )*(1.15)*(sin90)*v = (7.728*10^{-6})*(v)$

$F_{x2}$ is in the positive x direction as $F_{x1}$ is in the negative x direction while net force is in the positive x direction.

Magnetic field is in the positive Z direction, net force is in the positive x direction.

According to right hand rule, Force acting on particle is perpendicular to the direction of magnetic field and velocity of particle. This would mean the force is along the y-axis. As this is a negatively charged particle, the direction of the velocity of the particle is reversed. Therefore velocity of particle, v, has to be in the negative y direction.

Now,

$F_{xnet}- F_{x1 } = F_{x2 }$

$(6.13*10^{-3}) - (8.53*10^{-3} ) = (7.728*10^{-6})*(v)$

$v = (F_{xnet} - F_{x1}) / (F_{x2} )$

$=((6.13*10^{-3} ) - (8.53*10^{-3})) / (7.728*10^{-6})$

$= (- 104.25) m/s$

$v_{y} = -104 m/s$

8 0

3 years ago