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3 years ago

How do you think density plays a role in the atmosphere?

1 answer:

4 0

Answer:
Also, gases like air are easily compressed. The weight of all the air above a given point in the atmosphere squeezes air molecules closer together. This causes the density to increase. The more air above a level (and hence the more weight of air above a level), the greater the compression.

Step By Step Explanation:

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3. A Tylenol has 80 mg of acetaminophen.<br> How many grams is that

denis23 [38]

$\boxed{\sf 1g=1000mg}$

$\\ \sf\longmapsto 80g$

$\\ \sf\longmapsto \dfrac{80}{1000}$

$\\ \sf\longmapsto 0.08g$

6 0

2 years ago

What is the Force in Newtons exerted by an object with a mass of 15 kg and an Acceleration of 12 m/s2?

ZanzabumX [31]

Force = mass * acceleration
F = ma
F = (15)(12)
F = 180N

5 0

3 years ago

The arrows in the chart below represent phase transitions.

Vikentia [17]

Answer:

1, 2, and 3.

Explanation:

Hello.

In this process, since the phase transitions that require energy are those that pass from a state with less energy or more molecular order to a state with more energy or less molecular order, say, from solid to liquid (melting), from liquid to gas (boiling) and from solid to gas (sublimation), we can conclude that the arrows representing heat energy gained are 1, 2, and 3 since 1 represents boiling, 2 melting and 3 sublimation.

Best regards.

6 0

2 years ago

Is it possible for an object to have a charge of 4.8x10-9 C? Why or why not?

Gelneren [198K]

I have absolutely no clue

3 0

3 years ago

A centrifuge in a medical laboratory rotates at an angular speed of 3,500 rev/min, clockwise (when viewed from above). When swit

Ratling [72]

Answer:

The magnitude of angular acceleration is $232.38\ rad/s^2$ .

Explanation:

Given that,

Initial angular velocity, $\omega_i=3500\ rev/min=366.5\ rad/s$

When it switched off, it comes o rest, $\omega_f=0$

Number of revolution, $\theta=46=289.02\ rad$

We need to find the magnitude of angular acceleration. It can be calculated using third equation of rotational kinematics as :

$\omega_f^2-\omega_i^2=2\alpha \theta\\\\\alpha =\dfrac{-\omega_i^2}{2\theta}\\\\\alpha =\dfrac{-(366.51)^2}{2\times 289.02}\\\\\alpha =-232.38\ rad/s^2$

So, the magnitude of angular acceleration is $232.38\ rad/s^2$ . Hence, this is the required solution.

6 0

3 years ago