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Lorico [155]
3 years ago
15

Please help me answer this question! I don’t understand it at all!

Chemistry
1 answer:
pentagon [3]3 years ago
7 0
The uncertainty principle is one of the most famous (and probably misunderstood) ideas in physics. It tells us that there is a fuzziness in nature, a fundamental limit to what we can know about the behaviour of quantum particles and, therefore, the smallest scales of nature. Of these scales, the most we can hope for is to calculate probabilities for where things are and how they will behave. Unlike Isaac Newton's clockwork universe, where everything follows clear-cut laws on how to move and prediction is easy if you know the starting conditions, the uncertainty principle enshrines a level of fuzziness into quantum theory.
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How many grams of CrSO3 are in 2.4 moles of CrSO3
castortr0y [4]

Answer: 316.8 g CrSO3

Explanation: Solution:

2.4 moles CrSO3 x 132 g CrSO3 / 1 mole CrSO3 = 316.8 g CrSO4

The conversion factor is 1 mole of CrSO4 is equal to its molar mass which is 132 g CrSO3

4 0
3 years ago
Which of the following is a physical property of nonmetals?
Minchanka [31]
The answer is (B) non metals are not very good at coducting electricity.
Hope this helps :).
5 0
3 years ago
Thorium-234 has a half-life of 24.1 days. How many grams of a 150 g sample would you have after 120.5 days?
chubhunter [2.5K]

Answer:

8.625 grams of a 150 g sample of Thorium-234  would be left after 120.5 days

Explanation:

The nuclear half life represents the time taken for the initial amount of sample  to reduce into half of its mass.

We have given that the half life of thorium-234 is 24.1 days. Then it takes 24.1 days for a Thorium-234 sample to reduced to half of its initial amount.

Initial amount of Thorium-234 available as per the question is 150 grams

So now  we start with 150 grams  of Thorium-234

150 \times \frac{1}{2}=24.1

75 \times \frac{1}{2} =48.2

34.5 \times \frac{1}{2} =72.3

17.25 \times \frac{1}{2} =96.4

8.625\times \frac{1}{2} =120.5

So after 120.5 days the amount of sample that remains is 8.625g

In simpler way , we can use the below formula to find the sample left

A=A_{0} \cdot \frac{1}{2^{n}}

Where

A_0  is the initial sample amount  

n = the number of half-lives that pass in a given period of time.

7 0
3 years ago
What is the mass of and object with a volume of 100 cm3 and a density of 10 g/cm3?
nadezda [96]

Answer:

1000 g

Explanation:

d = m/v

We are given d: 10g/cm3

and v: 100cm3

Plug them into the equation to get 10 = m/100

Then, cross multiply 10x100 to get mass which is: 1000g

4 0
3 years ago
Post laboratory reflections 1 write equation [2] in the net ionic form 2. describe what happens when strong acid acts on limesto
oee [108]
It deteriorates. Definitely more than when you started.

4 0
3 years ago
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