Answer:
19.3 L
Explanation:
V= n × 22.4
where V is volume and n is moles
First, to find the moles of CO2, divide 38.0 by the molecular weight of CO2 which is 44.01
n= m/ MM
n= 38/ 44.01
n= 0.86344012724
V= 0.86344012724 × 22.4
V= 19.3410588502 L
V= 19.3 L
Answer:
30 Liters of 40% acid solution and 10 L of 60% acid solution is needed.
Explanation:
Let volume of the 40% acid solution be x.
Let volume of the 60% acid solution be y.
Volume of solution formed after mixing both solution = 40 L
x + y = 40 L..[1]
Volume of acid 40% solution = 40% of x= 0.4x
Volume of acid 60% solution = 60% of y= 0.6y
Volume of acid formed = 45% of 40 L = 
..[2]
Solving [1] and [2]
x = 30 L , y = 10 L
30 Liters of 40% acid solution and 10 L of 60% acid solution is needed.
Answer:Molarity
Explanation:M stand for molarity
2NaBr + Ca(OH)2 ➡️ CaBr2 + 2NaOH
Answer:
10.32 moles of ammonia NH₃
Explanation:
From the question given above, the following data were obtained:
Number of molecules = 6.21×10²⁴ molecules
Number of mole of NH₃ =?
The number of mole of NH₃ can be obtained as follow:
From Avogadro's hypothesis,
6.02×10²³ molecules = 1 mole
Therefore,
6.21×10²⁴ molecules = 6.21×10²⁴ / 6.02×10²³
6.21×10²⁴ molecules = 10.32 moles
Thus, 6.21×10²⁴ molecules contains 10.32 moles of ammonia NH₃
