Answer:
The mass of silver carbonate precipitated is 5.18 grams.
Explanation:
Molarity of the silver nitrate solution = 0.671 M
Volume of the silver nitrate solution = 56.0 mL
![1 mL = 0.001 L\\56.0 mL = 56.0\times 0.001 L=0.0560 L](https://tex.z-dn.net/?f=1%20mL%20%3D%200.001%20L%5C%5C56.0%20mL%20%3D%2056.0%5Ctimes%200.001%20L%3D0.0560%20L)
Moles of silver nitrate = n
![Molarity=\frac{\text{Moles of compound}}{\text{Volume of solution in Liters}}\\\\0.671 M=\frac{n}{0.0560 L}\\n=0.671 M\times 0.0560 L=0.0376 mol](https://tex.z-dn.net/?f=Molarity%3D%5Cfrac%7B%5Ctext%7BMoles%20of%20compound%7D%7D%7B%5Ctext%7BVolume%20of%20solution%20in%20Liters%7D%7D%5C%5C%5C%5C0.671%20M%3D%5Cfrac%7Bn%7D%7B0.0560%20L%7D%5C%5Cn%3D0.671%20M%5Ctimes%200.0560%20L%3D0.0376%20mol)
Moles of silver nitrate used = 0.0376 mol
![K_2CO_3+2AgNO_3\rightarrow Ag_2CO_3+2KNO_3](https://tex.z-dn.net/?f=K_2CO_3%2B2AgNO_3%5Crightarrow%20Ag_2CO_3%2B2KNO_3)
According to the reaction, 2 moles of silver nitrate gives 1 mole of silver carbonate, then 0.0376 moles of silver nitrate:
![=\frac{1}{2}\times 0.0376 mol=0.0188 \text{mol of }Ag_2CO_3](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes%200.0376%20mol%3D0.0188%20%5Ctext%7Bmol%20of%20%7DAg_2CO_3)
Moles of the silver carbonate formed = 0.0188 mol
Molar mass of silver carbonate = 275.7453 g/mol
Mass of silver carbonate :
![=275.7453 g/mol\times 0.0188 mol=5.1840 g\approx 5.18 g](https://tex.z-dn.net/?f=%3D275.7453%20g%2Fmol%5Ctimes%200.0188%20mol%3D5.1840%20g%5Capprox%205.18%20g)
The mass of silver carbonate precipitated is 5.18 grams.
Answer:
The initial volume of the chlorine gas ![V1=733.28mL](https://tex.z-dn.net/?f=V1%3D733.28mL)
Explanation:
Given:
P1= 686mmHg
P2= 991mmHg
V2= 5076mL
V1=?
According to Boyle's law which states that at a constant temperature, the pressure on a gas increases as it's volume decreases.
It can be expressed as : P1V1 = P2V2
Where P1 is the initial pressure
P2= final pressure
V1= initial volume
V2 = final volume
![V1= (P2V2)/P1](https://tex.z-dn.net/?f=V1%3D%20%28P2V2%29%2FP1)
V1= (991mmHg*507.6mL)/686mmHg
V1=503031.6/686
![V1=733.28mL](https://tex.z-dn.net/?f=V1%3D733.28mL)
Therefore, The initial volume of the chlorine gas ![V1=733.28mL](https://tex.z-dn.net/?f=V1%3D733.28mL)
Answer:
E. Cool a solvent below room temperature
Explanation:
When a solution that has had more solute dissolved at a higher temperature is now cooled, it becomes supersaturated at the lower temperature. Because that supersaturated solution holds more solute than is stable at the lower temperature, crystals start to form.
Answer:
Semi-metals with propeties in between metals and non-metals
I need to know what goes in the blanks for the nuclear reactions
1.) ²³⁵92U → _____ + ²³¹90Th
Answer 1: ²³⁵92U → ⁴2He + ²³¹90Th
2.) ¹1H + ³1H → _____
Answer 2 : ¹1H + ³1H → ⁴2He
3.) ⁶3Li + ¹0n → ⁴2He + _____
Answer 3 : ⁶3Li + ¹0n → ⁴2He + ³1H
4.) ²⁷13Al + ⁴2He → ³⁰15P + ___
Answer 4 : ²⁷13Al + ⁴2He → ³⁰15P + ¹0n
5.) ⁹4Be + ¹1H → ___ + ⁴2He
Answer 5 : ⁹4Be + ¹1H → ⁶3Li + ⁴2He
6.) ³⁷19K → ⁰+1e⁻ + ____
Answer 6 : ³⁷19K → ⁰+1e⁻ + ³⁷19K⁺
Hope this helps!