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3 years ago

9

Each particular chemical reaction cannot be expected to occur at identical rates.

1 answer:

givi [52]3 years ago

4 0

Each particular chemical reaction cannot be expected to occur at identical rates.

True. Not all chemical reactions happen at the same rate, depending on the catalyst.

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Use the provided reduction potentials to calculate ArGº for the following balanced redox reaction: Pb2+(aq) + Cu(s) → Pb(s) + Cu

nydimaria [60]

Answer : The correct option is, +91 kJ/mole

Solution :

The balanced cell reaction will be,

$Cu(s)+Pb^{2+}(aq)\rightarrow Cu^{2+}(aq)+Pb(s)$

Here copper (Cu) undergoes oxidation by loss of electrons, thus act as anode. Lead (Pb) undergoes reduction by gain of electrons and thus act as cathode.

First we have to calculate the standard electrode potential of the cell.

$E^0_{[Pb^{2+}/Pb]}=-0.13V$

$E^0_{[Cu^{2+}/Cu]}=+0.34V$

$E^0_{cell}=E^0_{cathode}-E^0_{anode}$

$E^0_{cell}=E^0_{[Pb^{2+}/Pb]}-E^0_{[Cu^{2+}/Cu]}$

$E^0_{cell}=-0.13V-(0.34V)=-0.47V$

Now we have to calculate the standard Gibbs free energy.

Formula used :

$\Delta G^o=-nFE^o_{cell}$

where,

$\Delta G^o$ = standard Gibbs free energy = ?

n = number of electrons = 2

F = Faraday constant = 96500 C/mole

$E^o$ = standard e.m.f of cell = -0.47 V

Now put all the given values in this formula, we get the Gibbs free energy.

$\Delta G^o=-(2\times 96500\times (-0.47))=+90710J/mole=+90.71kJ/mole\approx +91kJ/mole$

Therefore, the standard Gibbs free energy is +91 kJ/mole

6 0

3 years ago

What is "change" when we are talking about natural and physical systems?

zlopas [31]

D: is the anwser that your looking for

4 0

3 years ago

Read 2 more answers

1: Scrieţi şi egalaţi ecuaţiile reacţiilor chimice de schimb prezentate mai jos: a) carbonat de sodiu + clorură de calciu = b) c

prisoha [69]

Answer:

AMBANTOT MO MALIGO KANA

5 0

3 years ago

Sugar costs $0.98/kg. 1 metric ton=1000 kg. How many metric tons of sugar can

EastWind [94]

Answer:

0.35714 Metric ton

Explanation:

350 / 0.98 = 357.1 ----------A

to get the answer on metric ton divide (a) by 1000

357.14/1000= 0.357

7 0

3 years ago

How many moles of NH3 can be produced from 30.0 mol of H2 and excess N2?

VMariaS [17]

20 mol of NH, can be produce from 30 mol o H2

6 0

3 years ago