Question

The density of ammonia gas under certain condition is 0.625 g/L. Calculate its density in g/cm³.

Answer 1

Explanation:

0,625 g/L =625000 g/cm3

Answer 2

Answer:

The density of Ammonia : 6.25.10⁻⁴ g/cm³

Further explanation  

Density is a quantity derived from the mass and volume  

Density is the ratio of mass per unit volume  

With the same mass, the volume of objects that have a high density will be smaller than objects with a smaller density  

The unit of density can be expressed in g/cm³ or kg/m³  

Density formula:  

\large {\boxed {\bold {\rho ~ = ~ \frac {m} {V}}}}ρ = Vm

ρ = density  

m = mass  

v = volume  

A common example is the water density of 1 gr/cm³  

Ammonia has a density of 0.625 g/L, then convert to g/cm³ :

\begin{gathered}\rm 1~L=1~dm^3=10^3~cm^3\\\\0.625~\dfrac{g}{L}\times \dfrac{1~L}{10^3~cm^3}\\\\\rho=\dfrac{0.625}{10^3}}\dfrac{g}{cm^3}=\boxed{6.25.10^{-4}\dfrac{g}{cm^3}}\end{gathered}

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