An object of mass 3.00kg, moving with an initial velocity of 5.00 i^ m/s , collides with and sticks to an object of mass 2.00 kg
1 answer:
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Explanation:
Formula which holds true for a leans with radii and
and index refraction n is given as follows.
Since, the lens is immersed in liquid with index of refraction . Therefore, focal length obeys the following.
and,
or,
= 32.4 cm
Using thin lens equation, we will find the focal length as follows.
Hence, image distance can be calculated as follows.
= 47.9 cm
Therefore, we can conclude that the focal length of the lens in water is 47.9 cm.
Answer:
W = 46 J
Explanation:
We need to find the angle between the two vectors Force vector and displacement vector.
First we will find the angle α of the force vector
Then we find the angle β of the displacement vector
With these two angles we can find the angle between the two vectors
∅ = α + β = 25.56 deg
The definition of work is given by the expression
The absolute value of F will be:
The absolute value of d will be:
Now we have: