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vichka [17]
3 years ago
8

The boy on the tower throws a ball 20m downrange. What is his pitching speed?

Physics
1 answer:
san4es73 [151]3 years ago
5 0

Answer:

The pitching speed of the ball is 19.7 m/s

Explanation:

  • Here, we can use the third equation of motion,  v^{2} = u^{2} - 2as
  • whereas v represents the final velocity, u represents initial velocity, a is the acceleration due to gravity and s is the displacement or distance an object traveled
  • Here, the initial velocity of the the ball is given as  zero and the acceleration due to gravity is 9.8  , the distance 's' is given as 20 m
  • Using the equation,  v^{2} = 2 * 9.8 * 20 = 392\\v = \sqrt{392} = 19.7m/s
  • Hence, the pitching speed of the ball is 19.7 m/s

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Answer:

(a) k = 30.33 N/m

(b) a = 9.8 m/s²

Explanation:

First, we need to find the force acting on the bungee jumper. Since, this is a free fall motion. Therefore, the force must be equal to the weight of jumper:

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Δx = change in length of bungee cord = 33 m - 12 m = 21 m

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637 N = k(21 m)

k = 637 N/21 m

<u>k = 30.33 N/m</u>

<u></u>

(b)

Since, this is free fall motion. Thus, the maximum acceleration will be the acceleration due to gravity.

a = g

<u>a = 9.8 m/s²</u>

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3 0
3 years ago
Read 2 more answers
ly charged particles are held 24 x 103m apart and then released from rest. The initial acceleration of the first particle is obs
inessss [21]

Answer:

Part a)

m_2 = 4.9 \times 10^7 kg

Part b)

q_1 = q_2 = 5312.6 C

Explanation:

Part a)

As we know that both charge particles will exert equal and opposite force on each other

so here the force on both the charges will be equal in magnitude

so we will have

F = m_1a_1 = m_2a_2

here we have

6.3 \times 10^7(7) = m_2(9)

now we have

m_2 = 4.9 \times 10^7 kg

Part b)

Now for the force between two charges we can say

F = \frac{kq_1q_2}{r^2}

now we have

(6.3 \times 10^7)(7) = \frac{(9\times 10^9)q^2}{(24\times 10^3)^2}

now we have

q_1 = q_2 = 5312.6 C

3 0
3 years ago
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