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LenaWriter [7]
3 years ago
7

How does subjustion change the ocean florr this is acctualy in science

Physics
1 answer:
JulijaS [17]3 years ago
7 0
Subductions causes the ocean floor to sink into deep-ocean trenches and the earths plates move apart from molten rock or magma ana the earths crusts rises a departs.
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What is the best definition Copernicus
cupoosta [38]

Answer:

(This can be a way to think about it) Nicholas Mikolaj Kopernik,1473–1543 Polish astronomer who declared the now accepted theory that the Earth and the other planets move around the Sun aka the Copernican System.

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Where does most of the oxygen at earth reside?
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Well most of the earth's oxygen resides in mineral oxides of the crust. a small fraction resides in the atmosphere and an even smaller fraction resides in the biosphere. still the biosphere is crucial to understanding the atmospheric oxygen budget as it controls short term exchanges between sediments and the atmosphere.
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QUESTION 1
Sveta_85 [38]

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3 years ago
A particle moves with a velocity    1 v 5j 3j 6k ms      under influence of a contact force  F 10i 10j 20k N.    
katrin2010 [14]

Answer:

P = 200 W

Explanation:

The expression for the power is

        P = W / t

the job

       W = F d

   

we substitute

      P = F d / t

      P = F. v

We apply this equation to our case where the velocity is

 v = (5 i + 3j + 6k) m / s

and the force is

 F = (10i + 10j +20 k) N

we substitute in the power equation, remember that the scalar product of the unit vectors is

i.i = j.j = k.k = 1 and the other products are zero

    P = 10 5 + 10 3 + 20 6

    P = 200 W

6 0
3 years ago
Two charged particles are accelerated through a uniform electric field and zero magnetic field, then enter a region with zero el
Mrac [35]

Answer:

Explanation:

In magnetic field , charged particle will have circular path . Let the radius of their circular path be r₁ and r₂ . Let their velocity at the time of entering magnetic field be v₁ and v₂ .

The velocity with which they will come out of electric field can be measured from following equation

Eq = 1/2 m v²  , E is electric field , q is charge on the particle , m is mass and v is velocity .

v² = 2Eq / m

radius of circular path can be measured by the following expression

m v² / r = Bqv

2Eq / r = Bqv

r = 2Eq / Bqv

= 2E / Bv

r² = 4E² / B²v²

= 4E²m / B²x 2Eq

since E , B and q are constant

r² = K . m

r₂² / r₁² = m₂ / m₁

1.5²

m₂ / m₁ = 1.5²

= 2.25

6 0
3 years ago
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