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Answer: A current of 1 A is flowing in a circuit if a charge of 1 coulomb passes any point in the circuit every second.
1 Amp = 1 Coulomb per second
We can write this formula as:
Current (I) = Charge (Q) / Time (t)
Charge (Q) = Current (I) x Time (t)
Explanation:
Answer:
The work done on the air is 4.699 x 10⁶ Joules
Explanation:
Given;
increase in air volume, ΔV = 0.227 m³
net pressure of the air, P = 2.07 x 10⁷ Pa
The work done on the air is given by;
W = PΔV
Where;
W is the work done on the air
P is the net pressure
ΔV is the increase in air volume
Substitute the given values and solve for work done;
W = (2.07 x 10⁷ Pa) (0.227 m³)
W = 4.699 x 10⁶ Joules
Therefore, the work done on the air is 4.699 x 10⁶ Joules
Answer:
80 N
Explanation:
From the question,
F = ma .......................... Equation 1
Where F = Force, m = mass of the object, a = acceleration of the object.
make m the subject of the equation
m = F/a.................... Equation 2
Given: F = 24 N, a = 3 m/s²
Substitute into equation 2
m = 24/3
m = 8 kg.
If the acceleration of the object becomes 10 m/s²,
Substitute into equation 1
F = 10(8)
F = 80 N.
