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1 year ago

when was the last year the theory of understanding the energetics and arrangement of atoms was developed

1 answer:

5 0

In 1897 the theory of understanding the energetics and arrangement of atoms was developed by Josheph Larmor.

It is also called solar system model of atom.

<h3>What is solar system model of atom? </h3>

The “solar system” model indicates an atom as a whole massive positive body that is the nucleus similar to the sun in the solar system with negative entities that are the electrons as the planets in our solar system revolving around it.

<h3>Why this model not accepted? </h3>

The thought about this model is that the electrons which revolves around the nucleus are the charged particles which have centripetal acceleration during the revolution. Even if they all are travelling at the same velocity in modulus, the trajectory of their velocity varies with respect to time which resulting in the centripetal acceleration. An accelerated charge particle will emit energy in the form of electromagnetic radiation. This results in the loss of energy which causes the charged particle to fall inside the nucleus. Therefore, this fails to happen.

Thus, we concluded that In 1897 the theory of understanding the energetics and arrangement of atoms was developed.

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Quiz time!

kykrilka [37]

potassium belongs to group IA of the periodic table.

7 0

3 years ago

Read 2 more answers

A volume of 90.0 mLmL of aqueous potassium hydroxide (KOHKOH) was titrated against a standard solution of sulfuric acid (H2SO4H2

Alja [10]

Answer:

0.823 M was the molarity of the KOH solution.

Explanation:

$H_2SO_4+KOH\rightarrow K_2SO_4+2H_2O$ (Neutralization reaction)

To calculate the concentration of base , we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $H_2SO_4$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is KOH.

We are given:

$n_1=2\\M_1=1.50 M\\V_1=24.7 mL\\n_2=1\\M_2=?\\V_2=90.0 mL$

Putting values in above equation, we get:

$2\times \1.50 M\times 24.7 mL=1\times M_2\times 90.0 mL$

$M_2=\frac{2\times 1.50M\times 24.7 mL}{1\times 90.0 mL}=0.823 M$

0.823 M was the molarity of the KOH solution.

7 0

3 years ago

If 23.5 g of magnesium occupies 13.5 cm^3 what is the density of magnesium

lara31 [8.8K]

The density of magnesium will be 1.74 g/cm³ if 23.5 g of magnesium occupies 13.5 cm³

<h3>What is Density ?</h3>

Density is the measurement of how tightly a material is packed together.

It is defined as the mass per unit volume.

Given ;

Mass = 23.5 g
Volume = 13.5 cm³

Formula to calculate density ;

Density = mass / volume

=23.5 / 13.5 = 1.74 g/cm³

Hence, the density of magnesium will be 1.74 g/cm³ if 23.5 g of magnesium occupies 13.5 cm³.

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4 0

2 years ago

Fictitious element X has an a average atomic mass of 254.9 and only 2 isotopes, One of its isotopes has an abundance of 72.00 an

elena-14-01-66 [18.8K]

Answer:

265.2amu

Explanation:

Given parameters:

Atomic mass = 254.9amu

Abundance of isotope 1 = 72%

Atomic mass of isotope 1 = 250.9amu

Abundance of isotope 2 = 100 - 72 = 28%

Unknown:

Atomic mass of isotope 2 = ?

Solution:

To find the atomic mass of isotope 2, use the expression below:

Atomic mass = (abundance of isotope 1 x atomic mass of isotope 1) + (abundance of isotope 2 x atomic mass of isotope 2)

Now insert the parameters and find the unknown;

254.9 = (0.72 x 250.9) + (0.28 x Atomic mass of isotope 2)

254.9 = 180.648 + 0.28x atomic mass of isotope 2

254.9 - 180.648 = 0.28x atomic mass of isotope 2

74.25 = 0.28 x atomic mass of isotope 2

Atomic mass of isotope 2 = 265.2amu

8 0

3 years ago

1. If you were working for a beverage company, which molarity would you recommend, and what directions for mixing would you crea

emmasim [6.3K]

Answer: I would prepare a standard solution

Explanation: A standard solution is a solution of known concentration (molarity). This is gotten from the stock using dilution principle. (C1V1=C2V2) I would prepare a 0.1M solution of the beverage into a standard 500ml flask.

7 0

3 years ago