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2 years ago

when was the last year the theory of understanding the energetics and arrangement of atoms was developed

1 answer:

5 0

In 1897 the theory of understanding the energetics and arrangement of atoms was developed by Josheph Larmor.

It is also called solar system model of atom.

<h3>What is solar system model of atom? </h3>

The “solar system” model indicates an atom as a whole massive positive body that is the nucleus similar to the sun in the solar system with negative entities that are the electrons as the planets in our solar system revolving around it.

<h3>Why this model not accepted? </h3>

The thought about this model is that the electrons which revolves around the nucleus are the charged particles which have centripetal acceleration during the revolution. Even if they all are travelling at the same velocity in modulus, the trajectory of their velocity varies with respect to time which resulting in the centripetal acceleration. An accelerated charge particle will emit energy in the form of electromagnetic radiation. This results in the loss of energy which causes the charged particle to fall inside the nucleus. Therefore, this fails to happen.

Thus, we concluded that In 1897 the theory of understanding the energetics and arrangement of atoms was developed.

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How are parentheses used in chemical formulas

Liula [17]

They make the symbols individual

6 0

3 years ago

Which member of each pair is more soluble in diethyl ether? Why?<br> (c) MgBr₂(s) or CH₃CH₂MgBr(s)

White raven [17]

CH3CH2MgBr is more soluble in diethyl ether .

We know that polar solvent dissolve in polar solvent very perfectly . as diethyl ether is a polar solvent so it have dipole -dipole interaction .

Hence the compound with similar interaction can dissolve in diethyl ether .

Here , MgBr2 is an ionic compound . there is ion-ion interactions occurs which is not similar to dipole -dipole interaction in diethyl ether .hence the solubility of MgBr2 in diethyl ether is less .

but in case of CH3CH2MgBr there are both polar and nonpolar end .CH3CH2 is the nonpolar end and MgBr is the polar end .

thus with the nonpolar end solute interact using depression forces and with polar end solute interact using dipole-dipole interaction . so CH3CH2MgBr is more soluble .

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4 0

2 years ago

Nitrogen and hydrogen combine at a high temperature, in the presence of a catalyst, to produce ammonia. N 2 ( g ) + 3 H 2 ( g )

Kisachek [45]

Answer:

After complete reaction, 0.280 moles of ammonia are produced

Explanation:

Step 1: Data given

Number of moles N2 = 0.140 moles

Number of moles H2 = 0.434 moles

Step 2: The balanced equation

N2(g) + 3H2 (g) ⟶ 2NH3 (g)

Step 3: Calculate the limiting reactant

For 1 mol N2 we need 3 moles H2 to produce 2 moles NH3

N2 is the limiting reactant. It will completely be consumed (0.140 moles).

H2 is in excess. There will react 3*0.140 = 0.420 moles

There will remain 0.434 - 0.420 = 0.014 moles

Step 4: Calculate moles NH3

For 0.140 moles N2 we'll have 2*0.140 = 0.280 moles NH3

After complete reaction, 0.280 moles of ammonia are produced

5 0

3 years ago

While analyzing a fingerprint, the forensic expert identified a ridge that had a short arm originating from it. Which ridge char

Diano4ka-milaya [45]

The answer is spur, hope this helped (:

7 0

3 years ago

How many moles are in 1.42 x 10^25<br> molecules of NaCl?

Sholpan [36]

<h3>Answer:</h3>

23.6 mol NaCl

<h3>General Formulas and Concepts:</h3>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

Reading a Periodic Table

<h3>Explanation:</h3>

<u>Step 1: Define</u>

1.42 × 10²⁵ molecules NaCl

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

Set up: $\displaystyle 1.42 \cdot 10^{25} \ molecules \ NaCl(\frac{1 \ mol \ NaCl}{6.022 \cdot 10^{23} \ molecules \ NaCl})$
Multiply/Divide: $\displaystyle 23.5802 \ mol \ NaCl$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

23.5802 mol NaCl ≈ 23.6 mol NaCl

3 0

3 years ago