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klio [65]
2 years ago
10

What is the electric flux passing through a gaussian surface that surrounds a 0.075 c point charge?

Physics
1 answer:
Valentin [98]2 years ago
7 0

An 0.075 c point charge's surrounding gaussian surface's electric flux  is 8.5 ×10⁹Nm²/C.

<h3>Which is a gaussian surface?</h3>

In three dimensions, the Gaussian surface is referred to as a closed surface where the flux of a vector field may be determined. The gravitational field, the electric field, or the magnetic field are all examples of these vector fields.

<h3>Why is a Gaussian surface drawn?</h3>

We build a fictitious Gaussian surface around the supplied surface when the surface of which an electric field or flux must be established is asymmetrical or the surface area is challenging to obtain, such as the surface area for an infinitely long wire or plane. The Gaussian surface is said to utilize symmetry the best.

When a charge q is surrounded by a gaussian surface, the electric flux that passes through it is

\phi=q / \epsilon 0= 0.075 / ( 8.85 ×10⁻¹²)

= 8.5 ×10⁹Nm²/C.

To know more about Gaussian Surface visit:

brainly.com/question/13003278

#SPJ4

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riving you along a highway at 35.0 m/s when you hear the siren of a police car approaching you from behind and you perceive the
Vaselesa [24]

Answer:

The speed of the police car is 33.98 m/s

Explanation:

Given;

first speed, v₁ = 35 m/s

first frequency, f₁ = 1370 Hz

second frequency, f₂ = 1330 Hz

second speed, v₂ = ?

Speed of sound is directly proportional to its frequency;

v = fλ

assuming the λ is constant, then,

\lambda = \frac{V}{F}\\\\\frac{V_1}{F_1} = \frac{V_2}{F_2}\\\\V_2 = \frac{V_1F_2}{F_1}\\\\V_2 =   \frac{35*1330}{1370}\\\\V_2 = 33.98 \ m/s

Therefore, the speed of the police car is 33.98 m/s

7 0
3 years ago
Reasons why inductors opposes charges passing through it<br>​
saul85 [17]

Answer:

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Explanation:

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8 0
3 years ago
If a 9 V battery with 4 Ω contact resistance is used and the relay has 80 Ω and the wire has 10 Ω/mile, what is the maximum tele
Sedaia [141]

Answer:

Telegraph distance will be 9.6 mile

Explanation:

We have given the voltage V = 9 volt

Contact resistance = 4 ohm

Relay resistance = 80 ohm

And wire has a resistance = 10 ohm/mile

We have given the current = 50 mA =0.05 A

According to ohm's law R=\frac{V}{I}=\frac{9}{0.05}=180ohm

So the resistance of wire = 180-4-80=96 ohm

So the length of the telegraph distance will be \frac{96}{10}=9.6mile

4 0
4 years ago
A wave that is traveling fast can be said to have a high ___
S_A_V [24]

A wave that is traveling fast can be said to have a high speed.<em> (b) </em>

Just like a car, motorcycle, or freight train that is traveling fast.

3 0
4 years ago
Two moles of neon gas at 25oC and 2.0 atm is expanded to 3 times the original volume while the pressure is reduced to 1.0 atm. F
bazaltina [42]

Answer:

The end temperature is 174 °C

Explanation:

Ideal gases are a simplification of real gases that is done to study them more easily. It is considered to be formed by point particles, do not interact with each other and move randomly. It is also considered that the molecules of an ideal gas, in themselves, do not occupy any volume.

The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:  

P*V = n*R*T

where P is the gas pressure, V is the volume that occupies, T is its temperature, R is the ideal gas constant, and n is the number of moles of the gas.

So, being:

  • P= 2 atm
  • V=?
  • n= 2 moles
  • R= 0.082 \frac{atm*L}{mol*K}
  • T= 25 °C= 298 °K

and replacing:

2 atm*V= 2 moles* 0.082 \frac{atm*L}{mol*K} *298 K

you get:

V=\frac{2 moles* 0.082\frac{atm*L}{mol*K}  *298 K}{2 atm}

V= 24.436 L

Now, two moles of neon gas is expanded to 3 times the original volume while the pressure is reduced to 1.0 atm. Then you know:

  • P= 1 atm
  • V= 3*24.436 L=73.308 L
  • n= 2 moles
  • R= 0.082 \frac{atm*L}{mol*K}
  • T= ?

Replacing:

1 atm*73.308 L= 2 moles* 0.082 \frac{atm*L}{mol*K} *T

Solving:

T=\frac{1 atm*73.308 L}{2 moles* 0.082\frac{atm*L}{mol*K}}

T= 447 °K= 174 °C (being 0°C=273 °K)

<u><em>The end temperature is 174 °C</em></u>

5 0
3 years ago
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