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klio [65]
2 years ago
10

What is the electric flux passing through a gaussian surface that surrounds a 0.075 c point charge?

Physics
1 answer:
Valentin [98]2 years ago
7 0

An 0.075 c point charge's surrounding gaussian surface's electric flux  is 8.5 ×10⁹Nm²/C.

<h3>Which is a gaussian surface?</h3>

In three dimensions, the Gaussian surface is referred to as a closed surface where the flux of a vector field may be determined. The gravitational field, the electric field, or the magnetic field are all examples of these vector fields.

<h3>Why is a Gaussian surface drawn?</h3>

We build a fictitious Gaussian surface around the supplied surface when the surface of which an electric field or flux must be established is asymmetrical or the surface area is challenging to obtain, such as the surface area for an infinitely long wire or plane. The Gaussian surface is said to utilize symmetry the best.

When a charge q is surrounded by a gaussian surface, the electric flux that passes through it is

\phi=q / \epsilon 0= 0.075 / ( 8.85 ×10⁻¹²)

= 8.5 ×10⁹Nm²/C.

To know more about Gaussian Surface visit:

brainly.com/question/13003278

#SPJ4

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Answer:

a) K=E-\frac{kA^2}{18}

b) U=\frac{kA^2}{18}

Explanation:

The law of conservation of mechanical energy states that total mechanical energy remains constant during oscillation. Mechanical energy is defined as the sum of kinetic energy and potential energy:

E=U+K\\E=\frac{kx^2}{2}+\frac{mv^2}{2}

a) The position is one-third the amplitude. So, we have x=\frac{1}{3}A. Replacing and solving for K

E=\frac{k(\frac{1}{3}A)^2}{2}+K\\E=\frac{kA^2}{18}+K\\K=E-\frac{kA^2}{18}

b) The potential energy is defined as:

U=\frac{kx^2}{2}

Replacing:

U=\frac{k(\frac{1}{3}A)^2}{2}\\U=\frac{kA^2}{18}

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A industrial (large) pressure cooker operates at 275 kPa. Initially there is 10 kg of water at 20°C, the cooker is operated unt
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Answer:

Q_{in} = 25349.92\,kJ

Explanation:

Let establish a control volume in the industrial pressure cooker, which is a transient state system. From the First Law of Thermodynamics, the heating process is modelled:

Q_{in} + m_{1}\cdot h_{1} - m_{2}\cdot h_{2} = (m_{1}-m_{2})\cdot u_{2} - m_{1}\cdot u_{1}

The heat transfered to the cooker is:

Q_{in} = m_{2}\cdot h_{2} - m_{1}\cdot h_{1} + (m_{1}-m_{2})\cdot u_{2}-m_{1}\cdot u_{1}

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h_{1} = 83.915\,\frac{kJ}{kg}

State 2

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h_{2} = 2720.9\,\frac{kJ}{kg}

The heat transfered to the cooker is:

Q_{in} = (9\,kg)\cdot (2720.9\,\frac{kJ}{kg} ) - (10\,kg)\cdot (83.915\,\frac{kJ}{kg} ) + (1\,kg) \cdot (2540.1\,\frac{kJ}{kg} )-(10\,kg)\cdot (83.913\,\frac{kJ}{kg} )

Q_{in} = 25349.92\,kJ

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