Answer:
A smooth, possibly curved line that you judge to come closest to all the points i.e, best fit line.
Explanation:
Line of best fit is a line through a plot of data points that best expresses the relationship between those points. The statement <em>'A smooth, possibly curved line that you judge to come closest to all the points'</em> defines the best fit line.
The other options are incorrect because we do not represent the plot of data points by horizontal or vertical lines representing their average/ midpoint values.
<span>If Variable A is increased, Variable B will increase too. In a direct relationship, the two variables move in the same direction - if one increases, the other does too, and vice versa. In an inverse relationship, the two variables move in opposite directions - if one increases, the other decreases.</span>
Answer:
3.6 × 10⁵ N/C = 360 kN/C
Explanation:
Let R = 2.0 cm be the radius of the sphere and q = -8.0 nC be the charge in it. Let q₁ be the charge at radius r = 1.0 cm. Since the charge is uniformly distributed, the volume charge density is constant. So, q/4πR³ = q₁/4πr³
q₁ = q(r/R)³. The electric field due to q₁ at r is E₁ = kq₁/r² = kq(r/R)³/r² = kqr/R³
The electric field due to the point charge q₂ = 5.0 nC is E₂ = kq₂/r².
So, the magnitude of the total electric field at r = 1.0 cm is
E = E₁ + E₂ = kqr/R³ + kq₂/r² = k(qr/R³ + q₂/r²)
E = 9 × 10⁹(-8 × 10⁻⁹ C × 1 × 10⁻² m/(2 × 10⁻² m)³ + 5 × 10⁻⁹ C/(1 × 10⁻² m)²)
E = 9 × 10⁹(-1 × 10⁻⁵ + 5 × 10⁻⁵)
E = 9 × 10⁹(4 × 10⁻⁵)
E = 36 × 10⁴ N/C = 3.6 × 10⁵ N/C = 360 kN/C
Answer:
-67 m/s
Explanation:
We are given that
Mass of ball,m=0.4 kg
Initial speed,u=14 m/s
Impulse,I=-32.4 N-s
Time,t=27 ms=
We have to find the mass's velocity in the x- direction.
We know that
Substitute the values
Answer:
2.12×10^-2hour
Explanation:
Acceleration is defined as the change in velocity of a body with respect to time.
Using one of the equations of motion:
S = ut + 1/2at²
Where S is the distance traveled by the airplane
u is the initial velocity
a is its acceleration
t is the time of travel
Given a = 1.2×104 km/h²
u = 60km/hr
t= ?
S = 4km
Substituting the values given into the formula to get 't'
4 = 60t+1/2(1.2×10⁴)t²
4 = 60t+0.6×10⁴t²
0.6×10⁴t²+60t-4= 0
Factorizing the quadratic equation
t = -b±√b²-4ac/2a
Where a= 6000 b = 60 c = -4
t = -60±√60²-4(6000)(-4)/2(6000)
t = -60±√3600+96000/12000
t = -60±√99600/12000
t = -60±315.6/12000
t = -60+315.6/12000
t= 255.6/12000
t = 0.0212hour
t = 2.12×10^-2hour