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Stells [14]
2 years ago
6

500. ml of a solution containing 1. 5 m nh4cl(aq) is mixed with 500. ml of a solution containing 0. 50m of naoh(aq). what is the

ph of the final solution? (kb(nh3) = 1. 8 x 10-5)
Chemistry
1 answer:
Sladkaya [172]2 years ago
3 0

The pH of the solution is determined by the hydrogen ion concentration. The pH of the solution with 1.5 M NH4Cl and 0.50 M NaOH is 8.77.

<h3>What is pH? </h3>

The potential of the hydrogen ion in the given solution is called pH which determines the acidity and basicity of the solution.

Given

The molar concentration of 500 mL NH4Cl = 1.5 M

The molar concentration of 500 mL NaOH= 0.50 M

Kb (NH3) = 1.8 × 10 -5

First pOH is calculated as,

pOH = pKB + log [NH4Cl][NaOH]

= - log 1.8 × 10-5 + log [1.5][0.50]

= - log 1.8 × 10-5 + log [3]

= 4.744 + 0.477

= 5.221

Now, pH is calculated from pOH as,

pH + pOH = 14

pH = 14 – pOH

= 14 – 5.221

= 8.77

Thus we found that, 8.77 is the pH of the solution with 1.5 M NH4Cl and 0.50 M NaOH.

learn more about pH:

brainly.com/question/12942138

#SPJ4

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The answer is D: Saturated.

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A concentrated solution is one holding a relatively large amount of solute.  However, you can have concentrated solutions that are saturated and unconcentrated (the word for this is dilute) solutions that aren't saturated.  Therefore, we can say that because the crystal doesn't dissolve, this solution is saturated, but we can't say with certainty that it is concentrated.

Because the first three options are invalid, as described above, while the scenario does describe a saturated solution, D is the correct answer.

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