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0.85 moles formula units of lead nitrate will produce 0.57 moles formula units of chromium (III) nitrate.
<h3>Explanation</h3>Typically, the oxidation state of Pb in lead nitrate tend to be +2. In other words, Pb in lead nitrate tends to exist as ions. The formula for a nitrate ion is
. The charge on each of the nitrate ion is -1. The charge on the two ions should balance. As a result, each
ion in lead nitrate would pair up with two
ions. The formula for lead nitrate will be
. Each formula unit of lead nitrate will contain one
ion and two
ions.
The "III" in the name "chromium (III) nitrate" is a Roman Numeral. It indicates that the oxidation state of Cr in chromium (III) nitrate is +3. The Cr in that compound will exist as . Similarly, each
will pair up with three
ions. The formula for chromium (III) nitrate will be
. Each formula unit of chromium (III) nitrate will contain one
ion and three
ions.
0.85 moles formula units of lead nitrate will contain 0.85 × 2 = 1.7 moles of ions. Those nitrate ions will end up in 1.7 / 3 = 0.57 moles formula units of chromium (III) nitrate. As a result, the reaction will produce 0.57 moles formula units of chromium (III) nitrate.
The number of moles in each sample will be 0.391 moles, 30.7 moles, 0.456 moles, and 1350 moles
<h3>What is the number of moles?</h3>The number of moles of a substance is the ratio of the mass of the substance to the molar mass.
In other words; mole = mass/molar mass.
Thus:
- moles of 18.0 g
= 18.0/46
= 0.391 moles
- moles of 1.35 kg
= 1350/44
= 30.7 moles
- moles of 46.1 g
= 46.1/101.1
= 0.456 moles
- moles of 191.8 kg
= 191800/142
= 1350 moles
More on the number of moles of substances can be found here: brainly.com/question/1445383
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Answer:
La masa atómica del hierro es 55.847 gramos por mol.
Explanation:
Las masas molares de ,
,
y
son 53.940 gramos por mol, 55.935 gramos por mol, 56.935 gramos por mol y 57.933 gramos por mol, respectivamente. La masa atómica del hierro se determina mediante el siguiente promedio ponderado:
La masa atómica del hierro es 55.847 gramos por mol.