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Veronika [31]
3 years ago
13

The amount of space tgat matter occupies is referred to as...

Chemistry
2 answers:
Pie3 years ago
5 0

the amount of space that matter occupies is referred to as Volume

Marrrta [24]3 years ago
4 0
It is either mass or volume
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At what substrate concentration would an enzyme with a K_cat of 30.0 s⁻¹ and a Km of 0.0050 M operate at one-quarter of its maxi
Umnica [9.8K]

Answer:

The correct answer is option B.

Explanation:

Michaelis–Menten 's equation:

v=V_{max}\times \frac{[S]}{(K_m+[S])}=k_{cat}[E_o]\times \frac{[S]}{(K_m+[S])}

V_{max}=k_{cat}[E_o]

v = rate of formation of products

[S] = Concatenation of substrate = ?

[K_m] = Michaelis constant

V_{max}= Maximum rate achieved

k_{cat} = Catalytic rate of the system

E_o = initial concentration of enzyme

We have :

v=\frac{V_{max}}{4}

[S] =?

K_m=0.0050 M

v=V_{max}\times \frac{[S]}{(K_m+[S])}

\frac{V_{max}}{4}=V_{max}\times \frac{[S]}{(0.0050 M+[S])}

[S]=\frac{0.005 M}{3}=1.7\times 10^{-3} M

So, the correct answer is option B.

8 0
3 years ago
Is na=na+ reduced or oxidized
Sonbull [250]

Answer:

oxidized

Explanation:

Each sodium atom loses an electron to form a sodium ion.

8 0
3 years ago
How many grams are in 3.40 x 10^24 molecules of CH4
Arturiano [62]

Answer:

90.37 g

Explanation:

From Avogadro Number,

1 mole of every substance contains a particle number of 6.02×10²³

From the question,

1 mole of CH₄ contains 6.02×10²³ molecules.

But,

1 mole of CH₄ has a mass of 16 g

Therefore,

16 g of CH₄ contains 6.02×10²³ molecules

Then,

Y g will contain 3.4×10²⁴ molecules

Solve for Y

Y = (16× 3.4×10²⁴)/(6.02×10²³)

Y = 90.37 g

6 0
3 years ago
Which reaction shows decomposition?
Nina [5.8K]

Answer:

I think first one..........

6 0
3 years ago
Which of these is not true?
makvit [3.9K]

Answer:

C. Atoms have isotopes of an element have different numbers of protons.

Explanation:

The isotopes are the variation in the number of neutrons (neutral charge), with increases the weight of the atom, so the first one, is related to this one.

5 0
3 years ago
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