The question is in another language, so the English translation of the question is as follows:
Is salt-water a hom.ogeneous or heterogeneous mixture?
Answer:
Hom.ogenous mixture
Explanation:
There are two types of mixtures hom.ogenous and hetergenous. a heterogeneous mixture has two or more visible phases while a hom.ogeneous mixture is composed of a single visible phase.
The salt-water is hom.ogeneous because the solve dissolve evenly in throughout the entire salt-water sample and gives visible phase.
Hence, the correct option is "hom.ogenous mixture".
Answer:
Large change in temperature makes heat flow fast.
Explanation:
Answer:
1.7927 mL
Explanation:
The mass of solid taken = 4.75 g
This solid contains 21.6 wt% 
, thus,
Mass of = 
= 1.026 g
Molar mass of = 261.337 g/mol
The formula for the calculation of moles is shown below:
Thus,
Considering the reaction as:
1 moles of react with 1 mole of 
Thus,
0.003926 mole of react with 0.003926 mole of
Moles of = 0.003926 mole
Also, considering:
Molarity = 2.19 M
So,
Volume = 0.0017927 L
Also, 1 L = 1000 mL
<u>So, volume = 1.7927 mL</u>
Answer:
0.80m of KOH
Explanation:
Molality is an unit of concentration defined as the ratio between moles of solute and kg of solvent.
In the problem, the solute is KOH and solvent is water.
Moles of 36g KOH -Molar mass: 56.1g/mol- are:
36g KOH × (1mol / 56.1g) = <em>0.642 moles of KOH</em>
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Now, as density of water is 1g/mL, mass of 800mL of water is:
800mL × (1g / mL) × (1kg / 1000g) = <em>0.800kg of water</em>
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Thus, molality is:
0.642moles of KOH / 0.800kg = <em>0.80m of KOH</em>
