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Vsevolod [243]
3 years ago
8

A heat pump with refrigerant-134a as the working fluid is used to keep a space at 25°C by absorbing heat from geothermal water t

hat enters the evaporator at 500C at a rate of 0.065 kg/s and leaves at 40°C. The refrigerant enters the evaporator at 20°C with a quality of 23 percent and leaves at the inlet pressure as saturated vapor. The refrigerant loses 300 W of heat to the surroundings as it flows through the compressor and the refrigerant leaves the compressor at 1.4 MPa at the same entropy as the inlet. Determine: (a) The degrees of subcooling of the refrigerant in the condenser, b)-The mass flow rate of the refrigerant . (c) The heating load and the COP of the pump, and d)-The theoretical minimum power input to the compressor for the same heating load.
Engineering
1 answer:
Leno4ka [110]3 years ago
6 0

Answer:2.88

Explanation:

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3 years ago
A 1-mm-diameter methanol droplet takes 1 min for complete evaporation at atmospheric condition. What will be the time taken for
Svet_ta [14]

Answer:

Time taken by the 1\mu m diameter droplet is 60 ns

Solution:

As per the question:

Diameter of the droplet, d = 1 mm = 0.001 m

Radius of the droplet, R = 0.0005 m

Time taken for complete evaporation, t = 1 min = 60 s

Diameter of the smaller droplet, d' = 1\times 10^{- 6} m

Diameter of the smaller droplet, R' = 0.5\times 10^{- 6} m

Now,

Volume of the droplet, V = \frac{4}{3}\pi R^{3}

Volume of the smaller droplet, V' = \frac{4}{3}\pi R'^{3}

Volume of the droplet ∝ Time taken for complete evaporation

Thus

\frac{V}{V'} = \frac{t}{t'}

where

t' = taken taken by smaller droplet

\frac{\frac{4}{3}\pi R^{3}}{\frac{4}{3}\pi R'^{3}} = \frac{60}{t'}

\frac{\frac{4}{3}\pi 0.0005^{3}}{\frac{4}{3}\pi (0.5\times 10^{- 6})^{3}} = \frac{60}{t'}

t' = 60\times 10^{- 9} s = 60 ns

5 0
3 years ago
Saturated water vapor undergoes a throttling process from 1bar to a 0.35bar. What is the change in temperature for this process?
mamaluj [8]

Answer:

-25.63°C.

Explanation:

We know that throttling is a constant enthalpy process

      h_1=h_2

From steal table

We know that if we know only one property in side the dome then we will find the other property by using steam property table.

  Temperature at saturation pressure 1 bar is 99.63°C and  Temperature at saturation pressure 0.35 bar is about 74°C .

So from above we can say that change in temperature is -25.63°C.

But there is no any option for that .

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3 years ago
Bore = 3"
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I need help my self lol XD
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A common process for increasing the moisture content of air is to bubble it through a column of water. The air bubbles are assum
likoan [24]

Answer:

Explanation:

Assumptions is that

1. The flow is an unsteady one

2. Bubbles diameter is constant

3. The bubble velocity is slow

4. There is no homogenous reaction

5. It has a one dimensional flux model along the radial direction

5 0
3 years ago
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