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soldier1979 [14.2K]
2 years ago
15

The path taken to move items from their origin to their destination is known as which of the following?

Engineering
1 answer:
mrs_skeptik [129]2 years ago
7 0

Answer:d

Explanation:

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सत्य से अधिक उपयोगी एवं आज्ञापालन से श्रेष्ठ क्या है ?<br>answer fast plz​
PilotLPTM [1.2K]

Answer:

I hope this helps you

Explanation:

किसी की जान बचाने के लिए झूठ बोलना सत्य से अधिक उपयोगी है । अन्यायपूर्ण आज्ञा का विरोध आज्ञापालन से श्रेष्ठ है ।

5 0
2 years ago
Atmospheric pressure is measured to be 14.769 psia. a. What would be the equivalent reading of a water barometer (inches of H20)
Fofino [41]

Answer:

(a) water height =408.66 in.

(b) mercury height=30.04 in.

Explanation:

Given: P=14.769 psi     ( 1 psi= 6894.76 \frac{N}{m^2} )

we know that   P=\rho\times g\timesh

where \rho =Density,g=9.81\frac{m}{s^2}

     h=height.

Given that P=14.769 psi ⇒P= 101828.6 7\dfrac{N}{m^2}

(a) P=\rho_{w}\times g\times h_{w}  

     \rho_{w}=1000\frac{Kg}{m^3}

⇒101828.67=1000\times 9.81\times h_{w}

h_{w}=10.38 m

So water barometer will read 408.66 in.            (1 m=39.37 in)

(b)  P=\rho_{hg}\times g\times h_{hg}

     \rho_{hg}=13600

So 101828.67=13600\times 9.81\times h_{hg}

h_{hg}=0.763 m

So mercury barometer will read 30.04 in.

6 0
3 years ago
The primary of an ideal transformer has 400 turns and its secondary has 200 turns. Neglecting electrical losses, if the power in
Vanyuwa [196]

Answer:

A.C. Voltage (transformers only work with A.C.) from input (primary) to output (secondary) is purely a function of the turns ratio.

Explanation:

6 0
1 year ago
Subject : SCIENCE
Leviafan [203]

Answer:

Increase the eletric current

slow down the resistance

Explanation:

7 0
2 years ago
Thermodynamics fill in the blanks The swimming pool at the local YMCA holds roughly 749511.5 L (749511.5 kg) of water and is kep
Talja [164]

Answer:

95.914\ \text{GJ}

\$272.78

Explanation:

m = Mass of water = 749511.5 kg

c = Specific heat of water = 4182 J/kg ⋅°C

\Delta T = Change in temperature = 80.6-50=30.6^{\circ}\text{F}

Cost of 1 GJ of energy = $2.844

Heat required is given by

Q=mc\Delta T\\\Rightarrow Q=749511.5\times 4182\times 30.6\\\Rightarrow Q=95.914\times 10^9\ \text{J}=95.914\ \text{GJ}

Amount of heat required to heat the water is 95.914\ \text{GJ}.

Cost of heating the water is

95.914\times 2.844=\$272.78

Cost of heating the water to the required temperature is \$272.78.

7 0
2 years ago
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