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soldier1979 [14.2K]
3 years ago
15

The path taken to move items from their origin to their destination is known as which of the following?

Engineering
1 answer:
mrs_skeptik [129]3 years ago
7 0

Answer:d

Explanation:

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Ring rolling is a deformation process in which a thick-walled ring of smaller diameter is rolled into a thin-walled ring of larg
VMariaS [17]

Answer:

a)True

Explanation:

Rolling:

Rolling is a metal forming in which a material passes through two or more than two depends on conditions,rolls to produce the desired product.

Ring rolling:

 In ring rolling a thick ring compresses by rolls to produce the large diameter ring.Actually volume of material is constant so when diameter of ring increases then to compensate it, the thickness of ring reduces .In simple words we can say that in ring rolling a thick ring of smaller is rolled into a thin ring of larger diameter.  

6 0
3 years ago
36. What is mass? (4.4)
KatRina [158]

Answer:

Mass, in physics, quantitative measure of inertia, a fundamental property of all matter.

Explanation:

Mass is the matter that makes up objects

3 0
3 years ago
Air enters a compressor at 100 kPa and 25 ⁰C. It is compressed to 2 MPa and exits the compressor at 540 K. The compressor is at
AysviL [449]

Answer:

(a) The reversible work is 207 kJ/kg

(b) The irreversibility rate is -38.39 kJ/kg

Explanation:

State1 : p1 = 100kpa, T1= 25+273 =298k

From air table, h1 =298.18 kJ/kg, s10= 1.69528 kJ/kgK

State 2a:p2=2mpa,t2=540k (actual condition 2a)

h2a= 544.35 kJ/kg,s2a0=2.29906

actual work input to the compressor =wout=h1-h2+Qin

=298.18-544.35+(-150)kJ/kg(- sign indicate heat loss)

=(-246.17)kJ/kg(-ve sign indicates the work is given into the system

a) Reversible work= Win actual - any irreversiblities present

                             =246.17 + irreversibilty

b) irreversibility = T0(Entopy generation Sgen) for air, Sgen

                         =s20-s10-Rln(p2/p1), T0=250C

                         =(25+273)(s2a0-s10-Rlnp2/p1+Qout/Tsurr)

    = 298x[(2.29906-1.69528-0.287kJ/kgK xln(2000kpa/100) + 150 /298]

  = -38.39 kJ/kg

a)Reversible work = Win actual -any irreversiblities present                  

                           =246.17 + irreversibilty

                           =246.17+-38.39

                          =207 kJ/kg

8 0
3 years ago
There are three homes being built, each with an identical deck on the back. Each deck is comprised of two separate areas. One ar
9966 [12]

9514 1404 393

Answer:

  746.7 ft²

Explanation:

You can add them up, or you can take advantage of multiplication to make the repeated addition simpler.

  (112.5 ft² +136.4 ft²) +(112.5 ft² +136.4 ft²) +(112.5 ft² +136.4 ft²)

  = (3)((112.5 ft² +136.4 ft²) = 3(248.9 ft²) = 746.7 ft²

The total area of the decks on the 3 homes is 746.7 ft².

7 0
3 years ago
transformer has 26 turns on the primary coil and 720 turns on the secondary coil. If this transformer is to produce an output of
hram777 [196]
<h2>Corrected Question:</h2>

A step-up transformer has 26 turns on the primary coil and 720 turns on the secondary coil. If this transformer is to produce an output of 4100 V with a 16-mA current, what input current and voltage are needed?

<h2>Answer:</h2>

The input current and voltage needed are 443 mA and 148 V respectively.

<h2>Explanation:</h2>

In a step-up transformer, the relationship between the number of turns in its primary coil (N_{p}), the number of turns in its secondary coil (N_{s}), the input voltage (V_{p}), the output voltage (V_{s}), the input current (I_{p}), and the output current (I_{s}) is given by;

\frac{N_{s} }{N_{p} } = \frac{V_{s} }{V_{p} } = \frac{I_{p} }{I_{s} }

This implies that;

\frac{N_{s} }{N_{p} } = \frac{V_{s} }{V_{p} }  ---------------------(i)

\frac{N_{s} }{N_{p} } = \frac{I_{p} }{I_{s} }  ---------------------(ii)

From the question;

N_{p} = 26 turns

N_{s} = 720 turns

V_{s} = 4100V

I_{s} = 16mA = 16 x 10⁻³A

(a) Substitute these values into equation (ii) as follows;

\frac{720}{26} = \frac{I_{p} }{16*10^{-3}}

Solve for I_{p};

I_{p} = 720 x 16 x 10⁻³ / 26

I_{p} = 443 x 10⁻³

I_{p} = 443 mA

Therefore the input current needed is 443mA

(b) Also, substitute those values into equation (i) as follows;

\frac{720}{26} = \frac{4100 }{V_{p} }

Solve for V_{p};

V_{p} = 4100 x 26 / 720

V_{p} = 148 V

Therefore, the input current needed is 148 V

5 0
3 years ago
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