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7nadin3 [17]
2 years ago
11

Lightbulb A is marked "25 W 120V, "and lightbulb B is marked "100 W 120V " These labels mean that each lightbulb has its respect

ive power delivered to it when it is connected to a constant 120-V source.(f) Find the cost of running lightbulb A continuously for 30.0 days, assuming the electric company sells its product at 0.110 per kWh.
Physics
1 answer:
Dovator [93]2 years ago
3 0

The cost of running the lightbulb A for 30 days at 0.110 per KWh is 1.98

<h3>How to determine the energy </h3>

We'll beging by calculating the energy used by lightbulb A. This can be obtained as follow:

  • Power (P) = 25 watts = 25 / 1000 = 0.025 KW
  • Time (t) = 30 days = 30 × 24 = 720 h
  • Energy (E) =?

E = Pt

E = 0.025 × 720

E = 18 KWh

<h3>How to determine the cost for running the bulb for 30 days</h3>

The cost of running the bulb for 30 days can be obtained as follow:

  • Cost per KWh = 0.11
  • Energy (E) = 18 KWh
  • Cost =?

Cost = energy × Cost per KWh

Cost = 18 × 0.11

Cost = 1.98

Lean more about buying electrical energy:

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A box has the dimensions of 50 cm × 30 cm × 15 cm, weighs 150 N, and is to be
nadezda [96]

The surface can only withstand a pressure Face A (50cm × 30cm) and Face C (50cm × 15cm) as the surface can only withstand a pressure of 0.25 N/cm³.

<h3>What is pressure?</h3>

The physical force used to apply pressure to an object is defined as such. Per square inch of an object, a force is applied perpendicularly to its surface. For pressure, the fundamental formula is F/A. (Force per unit area). The Pascal is the unit of pressure (Pa).

The four different types of pressure are absolute, atmospheric, differential, and gauge pressure. Have you ever noticed that when you use a straw to drink something, the air actually gets suked out? In reality, you're applying "Pressure" as you drink the beverage.

A box has the dimensions of 50 cm × 30 cm × 15 cm

Let each face be A, B and C

The weight of the box = 150 N

Formula for pressure is

P = F/A

To find out which face of the box can withstand a pressure of 0.25 N/cm

we need find the area of each face and find its pleasure

Face A = 50 cm × 30 cm

Area A = l × b

            = 50 × 30

            = 1500 cm²

Pressure A = 150/1500

                  = 0.1 N/cm³

                    0.25 > 0.1

The surface can definitively withstand the pressure of Face A

Face B = 30 cm × 15 cm

Area A = l × b

            = 30 × 15

            = 450 cm²

Pressure A = 150/450

                  = 0.3 N/cm³

                    0.25 < 0.3

The surface could not withstand the pressure of Face B

Face C = 50 cm × 15 cm

Area A = l × b

            = 50 × 15

            = 750 cm²

Pressure A = 150/750

                  = 0.2 N/cm³

                    0.25 > 0.2

The surface can definitively withstand the pressure of Face C

Thus, The surface can only withstand a pressure Face A (50cm × 30cm) and Face C (50cm × 15cm) as the surface can only withstand a pressure of 0.25 N/cm³.

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The specific heat capacity of sea water is 4100 J/Kg°C and the boiling point of 100.6 °C. (i) Calculate the energy required to r
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