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ELEN [110]
2 years ago
6

Which of these is

Physics
2 answers:
Airida [17]2 years ago
8 0

Answer:c

Explanation:work is force x distance. The wall doesn’t move any distance in A so that’s not work. B involves tasks that do work but I don’t think this is what they’re going for. For a short instance while kicking a ball, your foot is applying a force to the ball which moves a distance before following its own trajectory after contact with your foot. Because the contact has a short duration and isn’t instantaneous, this is work

irga5000 [103]2 years ago
7 0
In physics, work is the energy transferred to or from an object via the application of force along a displacement.
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a bowling ball because it has the most mass.

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Robert hook used an early microscope to observed a cork sample. How did this help contribute to cell theory?
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A spaceship hovering over the surface of Venus drops an object from a height of 17 m. How much longer does it take to reach the
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1.96s and 1.86s. The time it takes to a spaceship hovering the surface of Venus to drop an object from a height of 17m is 1.96s, and the time it takes to the same spaceship hovering the surface of the Earth to drop and object from the same height is 1.86s.

In order to solve this problem, we are going to use the motion equation to calculate the time of flight of an object on Venus surface and the Earth. There is an equation of motion  that relates the height as follow:

h=v_{0} t+\frac{gt^{2}}{2}

The initial velocity of the object before the dropping is 0, so we can reduce the equation to:

h=\frac{gt^{2}}{2}

We know the height h of the spaceship hovering, and the gravity of Venus is g=8.87\frac{m}{s^{2}}. Substituting this values in the equation h=\frac{gt^{2}}{2}:

17m=\frac{8.87\frac{m}{s^{2} } t^{2}}{2}

To calculate the time it takes to an object to reach the surface of Venus dropped by a spaceship hovering from a height of 17m, we have to clear t from the equation above, resulting:

t=\sqrt{\frac{2(17m)}{8.87\frac{m}{s^{2} } }} =\sqrt{\frac{34m}{8.87\frac{m}{s^{2} } } }=1.96s

Similarly, to calculate the time it takes to an object to reach the surface of the Earth dropped by a spaceship hovering from a height of 17m, and the gravity of the Earth g=9.81\frac{m}{s^{2}}.

t=\sqrt{\frac{2(17m)}{9.81\frac{m}{s^{2} } }} =\sqrt{\frac{34m}{9.81\frac{m}{s^{2} } } }=1.86s

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