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blagie [28]
3 years ago
6

Solve the system. 2x + y = 3 −2y = 14 − 6x Write each equation in slope-intercept form. y = x + y = x +

Physics
2 answers:
Marat540 [252]3 years ago
8 0
<span>3 equations in slope intercept form: y = -2/3·x + 1 y = -8x + 14 y = 3x - 11/2 Solution: (39/22, -2/11) We have a set of 3 equations, that we can create 3 lines from. So let's do so: 2x + y = 3 â’2y = 14 â’ 6x Line 1: 2x + y = 3 - 2y 2x = 3 - 3y 2x - 3 = -3y -2/3·x + 1 = y y = -2/3·x + 1 Line 2: 2x + y = 14 - 6x y = 14 â’ 8x y = -8x + 14 Line 3: 3 - 2y = 14 â’ 6x -2y = 11 â’ 6x y = -11/2 + 3x y = 3x - 11/2 So the 3 equations are: (1) y = -2/3·x + 1 (2) y = -8x + 14 (3) y = 3x - 11/2 Let's subtract equation (3) from equation (2) and solve for x. y = -8x + 14 y = 3x - 11/2 0 = -11x + 19.5 11x = 19.5 22x = 39 x = 39/22 We now have an X value of 39/22. Let's verify that the y values match. (1) y = -2/3·x + 1 y = -2/3·39/22 + 1 y = -78/66 + 1 y = -13/11 + 1 y = -2/11 (2) y = -8x + 14 y = -8·39/22 + 14 y = -312/22 + 14 y = -156/11 + 14 y = -2/11 (3) y = 3x - 11/2 y = 3·39/22 - 11/2 y = 117/22 - 11/2 y = 117/22 - 121/22 y = -4/22 y = -2/11 And they all match.</span>
KonstantinChe [14]3 years ago
5 0

y=-2x+3

y=3x+-7

How do the slopes and y–intercepts of the two equations compare? The slopes and the y-intercepts are different.




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When water vapor is cooled it three forms into water droplets why does this represent a conservation in mass
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3 years ago
If the mass of the ladder is 12.0 kgkg, the mass of the painter is 55.0 kgkg, and the ladder begins to slip at its base when her
Marysya12 [62]

Answer:

 μ = 0.336

Explanation:

We will work on this exercise with the expressions of transactional and rotational equilibrium.

Let's start with rotational balance, for this we set a reference system at the top of the ladder, where it touches the wall and we will assign as positive the anti-clockwise direction of rotation

          fr L sin θ - W L / 2 cos θ - W_painter 0.3 L cos θ  = 0

          fr sin θ  - cos θ  (W / 2 + 0,3 W_painter) = 0

          fr = cotan θ  (W / 2 + 0,3 W_painter)

Now let's write the equilibrium translation equation

     

X axis

        F1 - fr = 0

        F1 = fr

the friction force has the expression

       fr = μ N

Y Axis

       N - W - W_painter = 0

       N = W + W_painter

       

we substitute

      fr = μ (W + W_painter)

we substitute in the endowment equilibrium equation

     μ (W + W_painter) = cotan θ  (W / 2 + 0,3 W_painter)

      μ = cotan θ (W / 2 + 0,3 W_painter) / (W + W_painter)

we substitute the values ​​they give

      μ = cotan θ  (12/2 + 0.3 55) / (12 + 55)

      μ = cotan θ  (22.5 / 67)

      μ = cotan tea (0.336)

To finish the problem, we must indicate the angle of the staircase or catcher data to find the angle, if we assume that the angle is tea = 45

       cotan 45 = 1 / tan 45 = 1

the result is

    μ = 0.336

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Answer:

Explanation:

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