The Peak power output of the motor is 0.452 Watt
To find the peak power output, the given values are,
No .of turns of the wire = 80
Dimensions is given as, 2.50 cm by 4.00 cm
Magnetic field = 0.800 T.
current = 10 mA.
Angular speed = 3.60 ×10³ rev/min
<h3>What is Peak power output?</h3>
- Peak power output can be also known as Peak work rate.
- If the output was greatest or the work production was very high in the given amount of time then it is known as Peak power output.
- This peak power is depends on the force, distance and time.
The formula for peak power output,
Pout = τ * ω
where,
Pout - output power watts (W),
τ - torque Newton meters (Nm),
ω - angular speed radians per second (rad/s).
Calculating angular speed as here rotational speed of the motor in rpm is given:
ω = rpm * 2π / 60
where,
ω – angular speed, radians per second (rad/s),
rpm – rotational speed in revolutions per minute,
π – mathematical constant pi (3.14),
60 – number of seconds in a minute.
So, the formula is,
Peak power output = τ *rpm * 2π / 60
τ = NIAB sinθ Nm
= 80×10×10⁻³×0.0250×0.040×0.800× Sin 90°
= 2 × 6.4 × 10 ⁻⁴
= 1.2 × 10⁻⁴ Nm.
Peak power output = 1.2 × 10⁻⁴ ×3.60×10³ × 2π / 60
= 0.452 Watt
Thus, the peak power output is 0.452 Watt.
Learn more about Peak power output,
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