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Shalnov [3]
3 years ago
14

Which ball (if either) has the greatest speed at the moment of impact

Physics
2 answers:
Ierofanga [76]3 years ago
5 0
Are there any options??


I would have to say metal of course but without options I can't assume anything
Alenkinab [10]3 years ago
4 0
Whichever ball is placed higher, but if the balls are at the same level then both experience the same acceleration thus same speed.
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A space vehicle approaches a space station in orbit. The intent of the engineers is to have the vehicle slowly approach, reducin
N76 [4]

Answer: The total momentum before the docking maneuver is mV_{1}+MV_{2} and after the docking maneuver is (m+M) U

Explanation:

Linear momentum p (generally just called momentum) is defined as mass in motion and is given by the following equation:  

p=m.v  

Where m is the mass of the object and v its velocity.

According to the conservation of momentum law:

<em>"If two objects or bodies are in a closed system and both collide, the total momentum of these two objects before the collision </em>p_{i} <em>will be the same as the total momentum of these same two objects after the collision </em>p_{f}<em>". </em>

<em />

p_{i}=p_{f}

This means, that although the momentum of each object may change after the collision, the total momentum of the system does not change.

Now, the docking of a space vehicle with the space station is an inelastic collision, which means both objects remain together after the collision.

Hence, the<u> initial momentum</u> is:

p_{i}=mV_{1}+MV_{2}

Where:

m is the mass of the vehicle

V_{1} is the velocity of th vehicle

M is the mass of the space station

V_{2} is the velocity of the space station

And the <u>final momentum</u> is:

p_{f}=(m+M)U

Where:

U is the velocity of the vehicle and space station docked

6 0
3 years ago
Read 2 more answers
A mass m = 14 kg is pulled along a horizontal floor with NO friction for a distance d =5.7 m. Then the mass is pulled up an incl
frosja888 [35]

Answer:

W ≅ 292.97 J

Explanation:

1)What is the work done by tension before the block goes up the incline? (On the horizontal surface.)

Workdone by the tension before the block goes up the incline on the horizontal surface can be calculated using the expression;

W = (Fcosθ)d

Given that:

Tension of the force = 62 N

angle of incline θ =  34°

distance d =5.7 m.

Then;

W = 62 × cos(34) × 5.7

W = 353.4 cos(34)

W = 353.4 × 0.8290

W = 292.9686 J

W ≅ 292.97 J

Hence,  the work done by tension before the block goes up the incline = 292.97 J

8 0
3 years ago
The length of a rectangle is increasing at a rate of 4 cm/s and its width is increasing at a rate of 6 cm/s. When the length is
Fudgin [204]

Answer:

24cm/s

Explanation:

A=L*w

A'=L'*w'

L=13

w=5

L'=4

w'=6

A=?

A'=?

A=L*w

A=13*5

A=65

A'=L'*w'

A'=4*6

A'=24

*the given lengths are just to throw you off*

3 0
3 years ago
an airplane is taking off from an airport with velocity of 200 km/h at an angle of 30 degrees above horizontal how fast is its r
ddd [48]
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7 0
2 years ago
What are organs made of?
natita [175]
Organs are made of tissues

Tissues are made of cells though so it’s kinda a weird question lol
7 0
2 years ago
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