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3 years ago

What is the number of atoms per unit cell for each metal?

1 answer:

4 0

In the question, the number of atoms per unit cell is required for:
A) Polonium (Po)
In polonium, the structure is simple cubic, meaning there are 8 corner atoms, which add up to one atom per unit cell.

B) Manganese (Mn)
The structure of the Mn can be considered to be a body centered cubic (BCC) and the number of atoms for this is 8 corner atoms and 1 central atoms, making a total of 2 atoms per unit cell.

C) Silver (Ag)
Silver has a face centered cubic (FCC) unit cell structure, where there are 8 corner atoms and 6 atoms on the faces, so there are a total of 4 atoms per unit cell.

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What is the pH of a solution of RbOH with a concentration of 0.86 M? Answer to 2 decimal places

lubasha [3.4K]

Answer:The pH of the solution is given by pH=−log([H3O+])

Explanation:so you can't use

−

log

(

0.150

)

because that's the concentration of the hydroxide anions,

−

, not of the hydronium cations,

. In essence, you calculated the

pOH

of the solution, not its

Sodium hydroxide is a strong base, which means that it dissociates completely in aqueous solution to produce hydroxide anions in a

mole ratio.

NaOH

(

)

→

(

)

−

(

)

So your solution has

[

−

]

[

NaOH

]

0.150 M

Now, the

pOH

of the solution can be calculated by using

pOH

−

log

(

[

−

]

)

−−−−−−−−−−−−−−−−−−−−

In your case, you have

pOH

−

log

(

0.150

)

0.824

Now, an aqueous solution at

∘

has

pH + pOH

−−−−−−−−−−−−−−so you can't use

−

log

(

0.150

)

because that's the concentration of the hydroxide anions,

−

, not of the hydronium cations,

. In essence, you calculated the

pOH

of the solution, not its

Sodium hydroxide is a strong base, which means that it dissociates completely in aqueous solution to produce hydroxide anions in a

mole ratio.

NaOH

(

)

→

(

)

−

(

)

So your solution has

[

−

]

[

NaOH

]

0.150 M

Now, the

pOH

of the solution can be calculated by using

pOH

−

log

(

[

−

]

)

−−−−−−−−−−−−−−−−−−−−

In your case, you have

pOH

−

log

(

0.150

)

0.824

Now, an aqueous solution at

∘

has

pH + pOH

−−−−−−−−−−−−−−

3 0

1 year ago

How do you write a message?

Vilka [71]

Answer:

re clear. Try to convey your meaning as simply as possible. Don't over-write or use exorbitant language. ...

Are complete. Include all relevant information. Think about the situation from your readers' perspective. ...

Are correct. Always proofread before sending any message.

Explanation:

5 0

3 years ago

Read 2 more answers

Draw the mechanism of polymerization of propylene with benzoyl peroxide. Show chemical structures and arrows and remember that r

allochka39001 [22]

Answer:

See explanation below

Explanation:

This mechanism of polimerization is of one type. This mechanism goes through free radical polimerization, which means that we use a initiator as the radical source, then, the polimerization begins with the breaking of the covalent bonds of that initiator. In this case the benzoyl peroxide. And this mechanism is given in three steps.

In the picture you have the mechanism in the 3 steps:

7 0

2 years ago

6.0 mol NaOH reacts with

lina2011 [118]

Taking into account the reaction stoichiometry, 2 moles of Na₃PO₄ can be produced when 6.0 mol NaOH reacts with 9.0 mol H₃PO₄.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

3 NaOH + H₃PO₄ → 3 H₂O + Na₃PO₄

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

NaOH: 3 moles
H₃PO₄: 1 mole
H₂O: 3 moles
Na₃PO₄: 1 mole

<h3>Limiting reagent</h3>

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

<h3>Limiting reagent in this case</h3>

To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 1 mole of H₃PO₄ reacts with 3 moles of NaOH, 9 moles of H₃PO₄ reacts with how many moles of NaOH?

$moles of NaOH=\frac{9 moles of H_{3} PO_{4} x3 moles of NaOH}{1 mole of H_{3} PO_{4}}$

moles of NaOH= 27 moles

But 27 moles of NaOH are not available, 6 moles are available. Since you have less moles than you need to react with 9 moles of H₃PO₄, NaOH will be the limiting reagent.

<h3>Moles of Na₃PO₄ formed</h3>

Considering the limiting reagent, the following rule of three can be applied: if by reaction stoichiometry 3 moles of NaOH form 1 mole of Na₃PO₄, 6 moles of NaOH form how many moles of Na₃PO₄?

$moles of Na_{3}P O_{4} =\frac{6 moles of NaOHx1 mole of Na_{3}P O_{4} }{3 moles of NaOH}$

<u><em>moles of Na₃PO₄= 2 moles</em></u>

Then, 2 moles of Na₃PO₄ can be produced when 6.0 mol NaOH reacts with 9.0 mol H₃PO₄.

Learn more about the reaction stoichiometry:

brainly.com/question/24741074

brainly.com/question/24653699

#SPJ1

8 0

2 years ago

3. How many atoms in 3.91 moles of sodium?

Gala2k [10]

Answer:

Explanation:

The formula for sodium is Na. It does not form a molecule in some way.

1 mol Na = 6.02*10^23 atoms

3.91 mol = x Cross multiply

x = 3.91 * 6.02 * 10^23

x = 23.65 * 10^23

x = 2.365 * 10^24

Scientific notation is always expressed as a number 1 ≤ x < 10

3 0

2 years ago