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sleet_krkn [62]

3 years ago

9

An organic compound, which has the empirical formula C12H25 has an approximate molar mass of 338 g/mol. What is its probable mol

ecular formula?

1 answer:

Marta_Voda [28]3 years ago

8 0

Answer:

C24H50

Explanation:

The empirical fomula's molar mass is 169.25 g/mol.

We know the molecular formula's molar mass is 338 g/mol.

338/169.25= 1.99 or approximately 2

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A clam farmer has been keeping records of the water temperature and the number of clams developing from fertilized eggs. The dat

adoni [48]

Answer:

The dependent variable is the number of clams developing from fertilized eggs.

The independent variable is the water temperature

The optimum temperature for clam development is 30 degrees centigrade.

Explanation:

The graph of the number of clams developing from fertilized eggs and water temperature is attached to this answer.

The independent variable is being manipulated in an experiment. As it changes, it produces a corresponding change in the dependent variable.

Here, the water temperature is the independent variable. As it changes, the number of clams developing from fertilized eggs (dependent variable) also changes alongside.

The optimum temperature is the temperature at which the greatest number of clams developing from fertilized eggs is produced. We can see from the graph that this temperature is 30 degrees centigrade.

6 0

3 years ago

Use the half-reaction method to balance the following equation in acidic solution. It is not necessary to include any phases of

yawa3891 [41]

Answer:

2H⁺ + 2MnO4⁻ + 3CN⁻ → 2MnO₂ + H₂O + 3CNO⁻

Explanation:

CN⁻ + MnO4⁻ → CNO⁻ + MnO₂

In right side permangante, with Mn element has +7 as oxidation number.

In the MnO₂, Mn acts with +4.

This is the half reaction of reduction, where the Mn has gained 3 electrons.

in right side, cianide with C element has +2 as oxidation number. In the anion cianate, C acts with +4.

The oxidation number has increased in this half reaction. It's oxidation where the C, has lost 2 elecontrons

( 4H⁺ + MnO4⁻ + 3e⁻ → MnO₂ + 2H₂O ) .2

(H₂O + CN⁻ → CNO⁻ + 2e⁻ + 2H⁺) .3

I have to add water, to ballance the amount of oxygens and protons to ballance H, in the opposite side

To ballance the half reactions, I have to multiply x2 (reduction) and x3 (oxidation) so I can cancel, the electrons.

2H⁺ + 2MnO4⁻ + 3CN⁻ → 2MnO₂ + H₂O + 3CNO⁻

The electrons are now cancelled, and I can also modify water. In reactant side I have 3H₂O and in product side, I have 4H₂O so, H₂O in right side is gone so I finally obtained 1 H₂O on left. I had 8H⁺ on right, and 6H⁺ on left, so finally I obtained 2H⁺ on right, and the protons of product side are gone.

6 0

3 years ago

Given that the molar mass of carbon is 12 g/mol and the molar mass of oxygen is 16 g/mol, calculate the molar mass of carbon dio

nekit [7.7K]

Molar mass of oxygen is:
M(O)=16 g/mol
Molar mass of carbon is:
M(C)=12 g/mol
Molar mass of carbon dioxide is:
M(CO2)=M(C)+2*M(O)
M(CO2)=12 g/mol+2*16g/mol
M(CO2)=44 g/mol

<span>Molar mass(M) is the mass of 1 mole of the substance (grams per mole of a compound).</span>

7 0

3 years ago

If you produced 76.10 grams of potassium chloride in the reaction how many grams of potassium were required?

11111nata11111 [884]

Answer:39.8375

Explanation:

The mole for the equation is 1:1

Then the molar mass of KCl is 74.5g

Molar mass of k is 39

74.5g of KCl gives 39g of k

76.10g of KCl gives xg of k

X= 76.10×39/74.5

X= 2967.9/7

X= 39.8375

6 0

3 years ago

What does I stand for?

tatuchka [14]

I: Current
V: Voltage
R: resistance
you’re welcome ;)

7 0

3 years ago

Read 2 more answers