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Gnom [1K]
2 years ago
11

Why do we need a “mole”?

Chemistry
2 answers:
Triss [41]2 years ago
7 0
The mole is important because it allows chemists to work with the subatomic world with macro world units and amounts
Ivan2 years ago
4 0
Wdym mole like the animal or something else ?
You might be interested in
HELP ME PLEASE (brainliest)
Aloiza [94]

Answer: i would say D or the last one.

Explanation: According to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants. The law of conservation of mass is useful for a number of calculations and can be used to solve for unknown masses, such the amount of gas consumed or produced during a reaction.

Hope this helps :) Can u plz mark me branliest

7 0
2 years ago
Which substances in the diagram are most unstable? positive values of enthalpy negative values of enthalpy negative values -50 t
NemiM [27]

Answer:

no  s e

Explanation:

tampocose

8 0
3 years ago
Read 2 more answers
Given the balanced equation representing a reaction:
Vladimir79 [104]

Answer:

Option A. Addition

Explanation:

Unsaturated compounds under goes addition reaction to produce saturated compounds..

In the equation given above i.e

H2C=CH2 + F–F —> FCH2CH2F

we can see that the double in H2C=CH2 disappear by the reaction of F–F to produce FCH2CH2F which has no double. This simply indicates that the F–F was added to H2C=CH2. Hence, the reaction is called addition reaction.

4 0
3 years ago
Phosphine, an extremely poisonous and highly reactive gas, will react with oxygen to form tetraphosphorus decoxide and water, as
erica [24]

<u>Answer:</u> The amount of P_4O_{10} formed is 469.8 grams.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     ......(1)

Given mass of phosphine = 225 g

Molar mass of phosphine = 34 g/mol

Putting values in equation 1, we get:

\text{Moles of phosphine}=\frac{225g}{34g/mol}=6.62mol

The given chemical reaction follows:

4PH_3(g)+8O_2(g)\rightarrow P_4O_{10}(s)+6H_2O(g)

Assuming that oxygen gas is present in excess, it is considered as an excess reagent.

Phosphine is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

4 moles of phosphine produces 1 mole of P_4O_{10}

So, 6.62 moles of phosphine will produce = \frac{1}{4}\times 6.62=1.655mol of P_4O_{10}

Now, calculating the mass of P_4O_{10} by using equation 1:

Molar mass of P_4O_{10} = 283.9 g/mol

Moles of P_4O_{10} = 1.655 moles

Putting values in equation 1, we get:

1.655mol=\frac{\text{Mass of }P_4O_{10}}{283.9g/mol}\\\\\text{Mass of }P_4O_{10}=(1.655mol\times 283.9g/mol)=469.8g

Hence, the amount of P_4O_{10} formed is 469.8 grams.

8 0
3 years ago
HOW DO I DO THIS PLEASE HELP I AM CRYING
Taya2010 [7]

Answer:

here's the set up for the right side

              BaSO4     +      HCl

Ba                1                     0

Cl                 0                    1

H                  0                    1

S                   1                    0

O                  4                    0

Explanation:

You only have to answer whats in the chemical compound so since there is no hydrogen in BaSO4, you can put 0 or leave it blank :)

8 0
3 years ago
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