Answer:
136.36 mL
Explanation:
Here we have to use the dilution formula
From C1V1= C2V2
Where;
C1= initial concentration of the solution= 12.0 M
C2= final concentration of the solution= 2.20 M
V1 = initial volume of the solution= 25.0 ml
V2= final volume of the solution= ?????
Then recall;
C1V1=C2V2
V2 = C1V1/C2
Substituting values from the parameters given;
V2= 12.0 × 25.0 / 2.20
V2= 136.36 mL
Answer:
The frog has 4 toes on each foot in the front, and 5 toes on each foot in the back.
Explanation:
Answer:
14175 j heat released.
Explanation:
Given data:
Mass of aluminium = 350.0 g
Initial temperature = 70.0°C
Final temperature = 25.0°C
Specific heat capacity of Aluminium = 0.9 j/g.°C
Heat changed = ?
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
Heat change:
ΔT = Final temperature - initial temperature
ΔT = 25.0°C - 70°C
ΔT = -45°C
Q = m.c. ΔT
Q = 350 g × 0.9 j/g.°C × -45°C
Q = -14175 j
The Plum Pudding model of the atom was like a modernchocolate chip cookie it had subatomic particles embedded inside it in no particular arrangement
the gold foil experiment proved that there was a lot of empty space in an atom Because of the launched Particles.mostly deflected but some went through the foil
Answer:
39.2 g
Explanation:
- 2Ni₂O₃(s) ⟶ 4Ni(s) + 3O₂(g)
First we <u>convert 55.3 grams of Ni₂O₃ into moles of Ni₂O₃</u>, using its<em> molar mass</em>:
- 55.3 g ÷ 165.39 g/mol = 0.334 mol Ni₂O₃
Then we <u>convert 0.334 moles of Ni₂O₃ into moles of Ni</u>, using the <em>stoichiometric coefficients of the balanced reaction</em>:
- 0.334 mol Ni₂O₃ *
= 0.668 mol Ni
Finally we <u>calculate how much do 0.668 Ni moles weigh</u>, using the<em> molar mass of Ni </em>:
- 0.668 mol Ni * 58.69 g/mol = 39.2 g
