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Charra [1.4K]
3 years ago
12

What is the thermal energy needed to completely melt 9.60 mol of ice at 0.0 C

Chemistry
2 answers:
jeka57 [31]3 years ago
5 0

Answer:

57.792 kJ

Explanation:

Molar enthalpy of fusion of the substance is defined as the energy required to convert the substance in solid state, at its melting point to liquid state at constant pressure and no change in temperature.

For example the energy required to convert 1 mole of water (ice) at 0°C to 1 mole of water (liquid) at 0°C is 6.02 kJ/mol.

<u>Thus, thermal energy required to convert 9.60 moles of ice is 6.02×9.60 kJ = 57.792 kJ</u>

inysia [295]3 years ago
4 0
The  thermal energy  needed to  completely  melt  9.60  mole  of ice  at  0.0 C  is    57.8   Kj

        Explanation
ice  melt  to  form   water

The molar  heat of fusion  for   water  is  6.02  Kj/mol
Thermal energy =  moles  x  molar  heat  of  fussion  for water

=9.6  mol  x6.02 kj/mol =57.8  Kj
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Answer: The freezing point and boiling point of the solution are -6.6^0C and 101.8^0C respectively.

Explanation:

Depression in freezing point:

T_f^0-T^f=i\times k_f\times \frac{w_2\times 1000}{M_2\times w_1}

where,

T_f = freezing point of solution = ?

T^o_f = freezing point of water = 0^0C

k_f = freezing point constant of water = 1.86^0C/m

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w_1= mass of solvent (water) = density\times volume=1.00g/ml\times 97.6ml=97.6g

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Now put all the given values in the above formula, we get:

(0-T_f)^0C=1\times (1.86^0C/m)\times \frac{(21.4g)\times 1000}{97.6g\times (62g/mol)}

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Elevation in boiling point :

T_b-T^b^0=i\times k_b\times \frac{w_2\times 1000}{M_2\times w_1}

where,

T_b = boiling point of solution = ?

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k_b = boiling point constant of water = 0.52^0C/m

i = vant hoff factor = 1 ( for non electrolytes)

m = molality

w_2 = mass of solute (ethylene glycol) = 21.4 g

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(T_b-100)^0C=1\times (0.52^0C/m)\times \frac{(21.4g)\times 1000}{97.6g\times (62g/mol)}

T_b=101.8^0C

Thus the boiling point of the solution is 101.8^0C

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