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natulia [17]
2 years ago
8

a rigid, 5.00-l container is filled with enough h2 so that the pressure is 0.543 atm at 30.9°c. a quantity of h2s is added to th

e container so that the new pressure is 1.166 atm at 30.9°c. finally a quantity of he is added to the container so that the final pressure of the mixture is 1.787 atm at 30.9°c. what is the mole fraction of each component of the mixture?
Chemistry
1 answer:
Gekata [30.6K]2 years ago
8 0

The correct answer is the mole fraction of H 2 gas = 0.303 and the mole fraction of H2S gas = 0.652

Partial pressure of h2 = 1.787 atm - 0.543 atm

Partial pessure of  h2= 1.244  atm

o 5.00L container at 30.9°C having the mixture of gases (h2s and h2) with given Pavial Ressures. Then then mole fractions =

Partial pressue of h2 = 0.543 atm

Partial pressure of h2s = 1.166 atm:

total partial pressure of the mixture (h2 and h2s) = 1.787 atm

According to Daltion low of partial pressures (from derivation)

Partial pressure of the gas= mole fraction x Total pressure

mole fraction=  Partial Pressure / Total Pressure.

So mole fraction of h2 =0.543 atm / 1.787 =0.303

mole fraction of H2s  =1.166/ 1.787 =0.652

According to Dalton's law of partial pressures, the total pressure of a gas mixture is equal to the sum of the partial pressures of the constituent gases

Learn more about Dalton's law of partial pressure here :-

brainly.com/question/14119417

#SPJ4

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