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hichkok12 [17]
3 years ago
11

Sea water, a solution composed of a variety of salts dissolved in water. the salt is the

Chemistry
1 answer:
luda_lava [24]3 years ago
4 0
In seawater, salt is the solute and water is the solvent.
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BRAINLIESTT ASAP! PLEASE HELP ME :)<br><br> Compare stored mechanical energy and mechanical energy.
UNO [17]

Stored mechanical energy is energy stored and awaiting to be used and mechanical energy is the energy that was stored being used.

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3 years ago
The book procedure calls for 2,5-dimethylhexane-2,5-diol and concentrated hydrochloric acid to be shaken in a reaction vial. Whi
san4es73 [151]

Answer:

E) All of the above.

Explanation:

Hello,

Since the acidic nature of the HCl implies its corrosiveness, when it is in contact with the skin and eyes the burning starts immediately, so gloves and goggles must be worn. Next, the fuming hydrochloric acid (37% by mass) is volatile so it gives off even when dissolved into water, so it must be used in the fume hood. Then, since vapors are produced during the chemical reaction, an overpressure could be attained, that's why we must keep the glass sash of the fume hood between us and the vial. As a common risk, the vial could be dropped causing the hydrochloric acid to splash, so we must keep the vial well inside the hood.

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7 0
3 years ago
Which of the following is an anion?
satela [25.4K]
A . O2- because it is a negatively charged ion
5 0
3 years ago
Which of the following statements is true about a hypothesis?
Tatiana [17]
A hypothesis is a prediction of what you believe to be true.
8 0
3 years ago
Read 2 more answers
A 1.28-kg sample of water at 10.0 °C is in a calorimeter. You drop a piece of steel with a mass of 0.385 kg at 215 °C into it. A
Kryger [21]

Answer:

T_{2}=16,97^{\circ}C

Explanation:

The specific heats of water and steel are  

Cp_{w}=4.186 \frac{KJ}{Kg^{\circ}C}

Cp_{s}=0.49 \frac{KJ}{Kg^{\circ}C}

Assuming that the water and steel are into an <em>adiabatic calorimeter</em> (there's no heat transferred to the enviroment), the temperature of both is identical when the system gets to the equilibrium T_{2}_{w}= T_{2}_{s}  

An energy balance can be written as

m_{w}\times Cp_{w}\times (T_{2}- T_{1})_{w}= -m_{s}\times Cp_{s}\times (T_{2}- T_{1})_{s}  

Replacing

1.28Kg\times 4.186\frac{KJ}{Kg^{\circ}C}\times (T_{2}-10^{\circ}C)= -0.385Kg\times 0.49 \frac{KJ}{Kg^{\circ}C} \times (T_{2}-215^{\circ}C)

Then, the temperature T_{2}=16,97^{\circ}C

8 0
3 years ago
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