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2 years ago

A bicyclist, initially at rest, begins pedaling and gaining speed steadily for 4.90s during which she covers 32.0m.

Physics

1 answer:

harina [27]2 years ago

3 0

Answer:

CHAPTER 1

Conceptual Problems

C1. A room in a house has a floor area of 120 ft2

. Which of the following is most likely the

approximate volume of the room?

a. 3 m3

b. 30 m3

c. 300 m3

d. 3 000 m3

C2. When SI units are plugged into an equation, it is found that the units balance. Which of the

following can we expect to be true for this equation?

a. The equation will be dimensionally correct.

b. The equation will be dimensionally correct except sometimes in cases when the right

hand side of the equation has more than one term.

c. The equation will not be dimensionally correct.

d. All constants of proportionality will be correct.

C3. How long has it been that scientists have accepted that the nucleus of the atom consists of

neutrons and protons? Think of your answers in terms of order of magnitude.

a. about a decade

b. about a century

c. about a thousand years

d. since Aristotle

C4. Consider the sine of any angle between 30°

and 40°

. If the angle were doubled, what would

happen to the sine of the angle?

a. It would double.

b. It would more than double.

c. It would increase but be less than double.

d. In different cases, it could do any of the above.

C5. There are other ways of expressing uncertainty besides significant figures. For example,

suppose a quantity is known to have a value between 20.4 and 20.0 and our best estimate of

the value is midrange at 20.2. We could write the number as 20.2 +/- 0.2 and say that the

number has a 1% uncertainty. We would also say it has 3 significant figures. If we square a

number with 1% uncertainty (i.e., 2 parts in about 200) and 3 significant figures, what

results?

a. A number with 1% uncertainty and 3 significant figures.

b. A number with 2% uncertainty and 3 significant figures.

c. A number with 2% uncertainty and 2 significant figures.

d. A number with 1% uncertainty and 2 significant figures.

You might be interested in

The acceleration due to gravity is higher on juniper Than on earth. The mass and weight of rock on juniper compared to that on e

soldier1979 [14.2K]

Answer:

2.5 times higher then that on the Earth

Explanation:

Gravity is higher on Jupiter then on Earth because Jupiter is much bigger, because of it's mass compared to Earth the gravity on Jupiter is about 2.4 - 2.5 times higher then Earths surface gravity which means a rock on Jupiter would be around "2.4 - 2.5 times as heavier then it would be on Earth."

Hope this helps.

3 0

2 years ago

A series circuit has a capacitor of 0.25 × 10⁻⁶ F, a resistor of 5 × 10³ Ω, and an inductor of 1H. The initial charge on the cap

viktelen [127]

Answer:

$q = (3 + e^{-4000 t} - 4 e^{-1000 t})\times 10^{-6}$

at t = 0.001 we have

$q = 1.55 \times 10^{-6} C$

at t = 0.01

$q = 2.99 \times 10^{-6} C$

at t = infinity

$q = 3 \times 10^{-6} C$

Explanation:

As we know that they are in series so the voltage across all three will be sum of all individual voltages

so it is given as

$V_r + V_L + V_c = V_{net}$

now we will have

$iR + L\frac{di}{dt} + \frac{q}{C} = 12 V$

now we have

$1\frac{d^2q}{dt^2} + (5 \times 10^3) \frac{dq}{dt} + \frac{q}{0.25 \times 10^{-6}} = 12$

So we will have

$q = 3\times 10^{-6} + c_1 e^{-4000 t} + c_2 e^{-1000 t}$

at t = 0 we have

q = 0

$0 = 3\times 10^{-6} + c_1 + c_2$

also we know that

at t = 0 i = 0

$0 = -4000 c_1 - 1000c_2$

$c_2 = -4c_1$

$c_1 = 1 \times 10^{-6}$

$c_2 = -4 \times 10^{-6}$

so we have

$q = (3 + e^{-4000 t} - 4 e^{-1000 t})\times 10^{-6}$

at t = 0.001 we have

$q = 1.55 \times 10^{-6} C$

at t = 0.01

$q = 2.99 \times 10^{-6} C$

at t = infinity

$q = 3 \times 10^{-6} C$

5 0

3 years ago

Alex swims at an average speed of 45 m/min.how far does he swim in 1min 24 sec?

Drupady [299]

Answer: 72m/1 min and 24 secs

Explanation:

He swims .75m/sec. im pretty sure i got it but let me know and ill help you out if its wrong

8 0

3 years ago

A railroad freight car rolls on a track at 3.50 m/s toward two identical coupled freight cars, which are rolling in the same dir

ladessa [460]

Answer:

Explanation:

Hello! To solve this problem we must be clear about the concept of energy conservation, and kinetic energy with the following sentence

The kinetic energy of the two cars (v = 1.2m / S) plus the kinetic energy of the third car (v = 3.5m / S) must be equal to the kinetic energy of the three cars together.

The kinetic energy is calculated by the following equation.

$E=0.5mV^2$