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AlekseyPX
2 years ago
7

A bicyclist, initially at rest, begins pedaling and gaining speed steadily for 4.90s during which she covers 32.0m.

Physics
1 answer:
harina [27]2 years ago
3 0

Answer:

CHAPTER 1

Conceptual Problems

C1. A room in a house has a floor area of 120 ft2

. Which of the following is most likely the

approximate volume of the room?

a. 3 m3

b. 30 m3

c. 300 m3

d. 3 000 m3

C2. When SI units are plugged into an equation, it is found that the units balance. Which of the

following can we expect to be true for this equation?

a. The equation will be dimensionally correct.

b. The equation will be dimensionally correct except sometimes in cases when the right

hand side of the equation has more than one term.

c. The equation will not be dimensionally correct.

d. All constants of proportionality will be correct.

C3. How long has it been that scientists have accepted that the nucleus of the atom consists of

neutrons and protons? Think of your answers in terms of order of magnitude.

a. about a decade

b. about a century

c. about a thousand years

d. since Aristotle

C4. Consider the sine of any angle between 30°

and 40°

. If the angle were doubled, what would

happen to the sine of the angle?

a. It would double.

b. It would more than double.

c. It would increase but be less than double.

d. In different cases, it could do any of the above.

C5. There are other ways of expressing uncertainty besides significant figures. For example,

suppose a quantity is known to have a value between 20.4 and 20.0 and our best estimate of

the value is midrange at 20.2. We could write the number as 20.2 +/- 0.2 and say that the

number has a 1% uncertainty. We would also say it has 3 significant figures. If we square a

number with 1% uncertainty (i.e., 2 parts in about 200) and 3 significant figures, what

results?

a. A number with 1% uncertainty and 3 significant figures.

b. A number with 2% uncertainty and 3 significant figures.

c. A number with 2% uncertainty and 2 significant figures.

d. A number with 1% uncertainty and 2 significant figures.

1

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Help with 1 2 and 3 please
geniusboy [140]

1. Amperes, is the SI unit (also a fundamental unit) responsible for current.

2. I = \frac{q}{t} Δq over Δt technically

Rearrange for Δq

I x Δt = Δq

1.5mA x 5 = Δq

Δq = 0.0075

Divide this by the fundamental charge "e"

Electrons: 0.0075 / 1.60 x 10^-19

Electrons: 4.6875 x 10^16 or 4.7 x 10^16

3.  So we know that the end resistances will be equal so:

ρ = RA/L

ρL = RA

ρL/A = R

Now we can set up two equations one for the resistance of the aluminum bar and one for the copper: Where 1 represents aluminum and 2 represents copper

\frac{p1L1}{A1}  = \frac{p2L2}{A2}\\

We are looking for L2 so we can isolate using algebra to get:

\frac{A2(\frac{P1L1}{A1}) }{P2} = L2

If you fill in those values you get 0.0205

or 2.05 cm



6 0
3 years ago
A straight line with a negative slope on a velocity-time graph indicates which of the following?
podryga [215]

Answer:

A

Explanation:

Straight line with a negative slope

On a velocity_time graph

5 0
3 years ago
The earth's radius is 6.37×106m; it rotates once every 24 hours. What is the earth's angular speed? What is the speed of a point
Zarrin [17]

Answer:

a) w = 7.27 * 10^-5 rad/s

b) v1 = 463.1 m/s

c) v1 = 440.433 m/s

Explanation:

Given:-

- The radius of the earth,  R = 6.37 * 10 ^6 m

- The time period for 1 revolution T = 24 hrs

Find:

What is the earth's angular speed?

What is the speed of a point on the equator?

What is the speed of a point on the earth's surface located at 1/5 of the length of the arc between the equator and the pole, measured from equator?

Solution:

- The angular speed w of the earth can be related with the Time period T of the earth revolution by:

                                  w = 2π / T

                                  w = 2π / 24*3600

                                  w = 7.27 * 10^-5 rad/s

- The speed of the point on the equator v1 can be determined from the linear and rotational motion kinematic relation.

                                 v1 = R*w

                                 v1 = (6.37 * 10 ^6)*(7.27 * 10^-5)

                                 v1 = 463.1 m/s

- The angle θ subtended by a point on earth's surface 1/5 th between the equator and the pole wrt equator is.

                                 π/2  ........... s

                                 x     ............ 1/5 s

                                 x = π/2*5 = 18°    

- The radius of the earth R' at point where θ = 18° from the equator is:

                                R' = R*cos(18)

                                R' = (6.37 * 10 ^6)*cos(18)

                                R' = 6058230.0088 m

- The speed of the point where θ = 18° from the equator v2 can be determined from the linear and rotational motion kinematic relation.

                              v2 = R'*w

                              v2 = (6058230.0088)*(7.27 * 10^-5)

                              v2 = 440.433 m/s

5 0
3 years ago
How does climate change?
Korvikt [17]

Answer:

Con el cielo del agua

Explanation:

espero que te ayude

5 0
2 years ago
Read 2 more answers
How to do this question
mestny [16]

thanks again and have to go to the store and get some rest I will be there at puno my phone is not working and I have a few questions about the week and I have a few questions about the week and I have a few questions about the week and I have a few questions about the week and I have a few questions about the week and I have a few questions about the week and I have a few questions about the week and I have a few questions about the week and I have a few questions about the week and I have a few questions about you

4 0
3 years ago
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