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3 years ago

The prevailing winds that form in hadley cells are ?

2 answers:

4 0

The Easterly Trade Winds and the Polar Easterlies have nothing over which to prevail, as their parent circulation cells are strong enough, and face few obstacles either in the form of massive terrain features or high pressure zones. The weaker Westerlies of the Ferrell cell, however, can be disrupted.

yarga [219]3 years ago

3 0

Answer:

Trade winds

Explanation:

The Trade winds are the wind that are generated in the Hadley cells. This wind occurs in the tropical region of both the hemisphere, covering from 0° to 30° latitude in both the hemisphere. This wind originates from the northeastern direction and blows towards the equator in the northern hemisphere, and on the other, this wind again blows from the southeastern direction and blows towards the equator in the southern hemisphere.They are also commonly known as the easterlies, as they move from the eastern to the western direction.

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USPshnik [31]

Answer:12

Explanation:

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3 years ago

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The momentum of an object is defined as the object's ________.

Gekata [30.6K]

Answer: C

Mass times its velocity

Explanation:

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3 years ago

If rho(x,y) is the density of a wire (mass per unit length), then

lidiya [134]

Answer:

See description

Explanation:

With the given information we have:

$x(t) = 1 + cos(t)\\ y(t)=sin(t)\\ \rho(x,y) = 3x$

the interval is $[0,\pi ]$

now the mass $m$ has the given expression:

$m = \int \rho(x,y) dS$

we will use the formula for a line integral and let:

$dS=\sqrt{x'(t)^2 + y'(t)^2}=\sqrt{cos(t)^2 + sin(t)^2}dt=dt$

therefore we have:

$m=\int \rho(x,y)dS=\int\limits^\pi_0 {3*x}dS=\int\limits^\pi _0{3*(1+cos(t))dS\\=\int\limits^\pi _0{3*(1+cos(t))dt$

we solve the integral:

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3 years ago

How long would it take a drag racer to increase her speed from 10m/s to 20 m/s if her car accelerates at a uniform rate of 15 m/

weeeeeb [17]

Answer:

t = 0.67 [s]

Explanation:

To solve this problem we must use the following kinematics equation.

$v_{f} =v_{i} +(a*t)\\where:$

Vf = final velocity = 20[m/s]

Vi = initial velocity = 10 [m/s]

a = aceleration = 15 [m/s^2]

Now replacing in the equation we have:

20 = 10 + (15*t)

t = (20-10)/15

t = 0.67 [s]

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3 years ago

What do you mean by mechanical advantage is 2.5 of a machine?

BigorU [14]

Answer:

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3 years ago