1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alecsey [184]
3 years ago
13

In the Bohr model of the atom, an electron in an orbit has a fixed ____.

Physics
1 answer:
worty [1.4K]3 years ago
3 0
The answer is C. an electron in an orbit has a fixed energy.
You might be interested in
What is the common phrase for natural selection
Rainbow [258]
Natrual selection is where animalz better adapt to their enviroment

7 0
3 years ago
Which research method uses questionnaires to collect information about the participants in a study?
Dima020 [189]
Survey research method uses questionnaires to collect information about the participants in a study.It is commonly used method of collecting information about a population of interest.
3 0
3 years ago
Read 2 more answers
A train goes up a hill with a 15º incline. If the train has constant speed of 22 m/s, what are the vertical and horizontal compo
Kobotan [32]
Any two-dimensional vector in cartesian (x,y) coordinates can be broken down into individual horizontal and vertical components using trigonometry. If a train goes up a hill with 15 degree incline at a speed of 22 m/s, the horizontal component is 22cos(15)=21.3 m/s and the vertical component is 22sin(15)=5.5 m/s. 
8 0
3 years ago
A sailboat moves north for a distance of 15.00 km when blown by a wind from the exact southeast with a force of 3.00 x 10^-4 N.
Zolol [24]
These are actually 4 different exercises:

ex 1) The sailboat moves north, while the wind moves from southeast. This means the angle between the direction of the boat and the wind is 45^{\circ}.

Calling F the force of the wind, and d=15~km=15000~m the distance covered by the boat, the work done by the wind is:
W=Fdcos{\theta}=3\cdot10^{-4}~N \cdot 15000~m\cdot cos 45^{\circ}=3.18~J

The total time of the motion is t=1~h=3600~s and therefore the power of the wind is
P= \frac{W}{t} = \frac{3.18~J}{3600~s}=8.8\cdot10^{-4}~W

ex 2) First of all, let's calculate the length of the ramp. Given the two sizes 2.00 m and 6.00 m, we have
d= \sqrt{(2~m)^2+(6~m)^2}= 6.32~m

The mechanical advantage (MA) of the ramp is the ratio between the output load (W) and the input force (F). The output load is the weight of the load, mg, therefore:
MA= \frac{W}{F}= \frac{mg}{F}= \frac{195~Kg\cdot 9.81~m/s^2}{750~N}=2.55

Finally, the efficiency \epsilon of the ramp is the ratio between the output energy and the work done. The output energy is simply the potential energy (Ep) of the load, which is mgh, where h is the height of the ramp. The work done W is the product between the input force, F, and the displacement of the load, which is the length of the ramp: Fd. Therefore:
\epsilon =  \frac{E_p}{W}= \frac{mgh}{Fd}= \frac{195~Kg \cdot 9.81~m/s^2\cdot 2~m}{750~N\cdot6.32~m}=0.81

ex 3) the graph is missing

ex 4) We know that the power is the ratio between the work done W and the time t:
P= \frac{W}{t}
But we can rewrite the work as
W=Fdcos\theta
where F is the force applied, d the displacement of rock and \theta=60^{\circ] is the angle between the direction of the force and the displacement (3 m). 
Therefore we can rewrite the power as
P= \frac{W}{t} = \frac{F d cos\theta}{t}=F v cos\theta
where v=d/t=5~m/s is the velocity, Using the data of the exercise, we can then find the force, F:
F= \frac{P}{v cos\theta} =   \frac{250~W}{5~m/s \cdot cos 60^{\circ}}=100~N

and now we can also calculate the work, which is 
W=Fdcos 60^{\circ}=100~N\cdot 3~m \cos60^{\circ}=150~J
3 0
3 years ago
The Indianapolis speedway consists of a 2.5 mile track having four turns, each 0.25 mile long and banked at 9 12'
blsea [12.9K]

Answer: Your question is missing below is the question

Question : What is the no-friction needed speed (in m/s ) for these turns?

answer:

20.1 m/s

Explanation:

2.5 mile track

number of turns = 4

length of each turn = 0.25 mile

banked at 9 12'

<u>Determine the no-friction needed speed </u>

First step : calculate the value of R

2πR / 4 =  πR / 2

note : πR / 2 = 0.25 mile

∴ R = ( 0.25 * 2 ) / π

      = 0.159 mile ≈ 256 m

Finally no-friction needed speed

tan θ = v^2 / gR

∴ v^2 = gR * tan θ

 v = √9.81 * 256 * tan(9.2°)  = 20.1 m/s

8 0
3 years ago
Other questions:
  • Describe what would happen if you rubbed a mineral with a Mohs hardness value of 7 against a mineral with a value of 5?
    9·1 answer
  • Watt, which is a unit of power, is equal to ____ a) a joule divided by a second b) a joule times a meter c) a joule times a seco
    7·2 answers
  • Critical thinking requires that _______. a. conclusions be held constant after their initial determination b. conclusions be adj
    13·2 answers
  • A geologist finds an area of undisturbed sedimentary rock the lowest layer is most likely the _____?
    8·1 answer
  • Electrical metallic tubing would be used in an electrical installation because it
    10·2 answers
  • Following are the different layers of the Sun's atmosphere. Rank them based on the order in which a probe would encounter them w
    7·1 answer
  • A TV draws 0.867 A of current when connected to a 122 V outlet. It’s resistance is 140.71.
    14·1 answer
  • Which of the following is the most important difference between a permanent magnet and a electromagnet
    6·1 answer
  • Where does the cart have the most velocity(speed)?
    14·2 answers
  • (b) Can the speed of a rocket exceed the exhaust speed of the fuel? Explain.
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!