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2 years ago

To determine whether a celestial body is approaching or receding from earth, astronomers employ?

1 answer:

7 0

To determine whether a celestial body is approaching or receding from Earth, astronomers employ The Doppler principle.

There is a Doppler effect for both light and sound.

For instance, astronomers regularly measure the amount to which a star or galaxy's light is "stretched" towards the lower frequency, red region of the spectrum to calculate how quickly the object is travelling away from us.

A wave's frequency changes in response to an observer moving in respect to the wave source, which is known as the Doppler effect or Doppler shift.

The Doppler effect results from the fact that as the wave source moves in the direction of the observer, the crest of each succeeding wave emerges from a location that is closer to the observer than the crest of the previous wave.

As a result, each wave travels to the observer slightly faster than the one before it. As a result, the interval between successive wave crests arriving at the observer is shorter, increasing the frequency.

Learn more about Doppler effect here brainly.com/question/4052291

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40 POINTS

goldenfox [79]

Answer:

<em>Well, I think the best answer will be is </em><em>B) Gravity. Good luck!</em>

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3 years ago

Read 2 more answers

Like the moon's orbit, Earth's orbit is not a perfect circle, but an oval How do you think this might affect Earth's tides?

ExtremeBDS [4]

During the parts in the orbit where the moon is farthest away from the earth the tides will be low. Whereas during the parts where the moon is closer to the earth the tides will be higher.

Good Luck!
Please correct me if i'm wrong

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3 years ago

A girl swings on a playground swing in such a way that at her highest point she is 4.1 m from the ground, while at her lowest po

Umnica [9.8K]

Answer:

V1 =8.1 m/s

Explanation:

height at highest point (h2) = 4.1 m

height at lowest point (h1) = 0.8 m

acceleration due to gravity (g) = 9.8 m/s^{2}

from conservation of energy, the total energy at the lowest point will be the same as the total energy at the highest point. therefore

mgh1 + $0.5mV1^{2}$ = mgh2 + $0.5mV2^{2}$

where

speed at highest point = V2

speed at lowest point = V1

mass of the girl and swing = m

at the highest point, the speed is minimum (V1 = 0)

at the lowest point the speed is maximum (V2 is the maximum speed)

therefore the equation becomes mgh1 + $0.5mV1^{2}$ = mgh2

m(gh1 + $0.5V1^{2}$ ) = m(gh2)

gh1 + $0.5V1^{2}$ = gh2

V1 = $\sqrt{\frac{gh2 - gh1}{0.5}}$

now we can substitute all required values into the equation above.

V1 = $\sqrt{\frac{(9.8x4.1) - (9.8x0.8)}{0.5}}$

V1 = $\sqrt{\frac{32.34}{0.5}}$

V1 =8.1 m/s

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4 years ago

Mutations can be transmitted to the next generation only if they are present in

emmainna [20.7K]

Answer:

The germline (the gametes)

Explanation:

Mutations are permanent changes in the DNA sequence. They can occur randomly, from mistakes during DNA replication, or as the result of external factors like UV radiation.

For these mutations to be passed on to the next generation, they must be present in the DNA of the gametes(i.e. the egg and sperm cells). This is because this is the DNA that goes on to make the offspring in the next generation following fertilisation.

If mutations are present in somatic cells (i.e. cells other than the gametes), they are not passed on to the next generation. For example, if someone gets mutations in their skin cells as a result of exposure to UV rays, this will not be passed on to their children.

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3 years ago

Where is energy being applied to the system?

Aleksandr-060686 [28]

Well i cant answer the first question due to absence of diagram
For the second queation, the energy affects the Frequency of wave, the higher the ebrgy the higher the frequency. Since frequency =1/Period,energy can also be said to alter the period. Since wave speed = Frequency *Wavelength, the speed is also increase due to increase in the frequency.
its amplitude increases too by the way.

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3 years ago