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2 years ago

To determine whether a celestial body is approaching or receding from earth, astronomers employ?

1 answer:

7 0

To determine whether a celestial body is approaching or receding from Earth, astronomers employ The Doppler principle.

There is a Doppler effect for both light and sound.

For instance, astronomers regularly measure the amount to which a star or galaxy's light is "stretched" towards the lower frequency, red region of the spectrum to calculate how quickly the object is travelling away from us.

A wave's frequency changes in response to an observer moving in respect to the wave source, which is known as the Doppler effect or Doppler shift.

The Doppler effect results from the fact that as the wave source moves in the direction of the observer, the crest of each succeeding wave emerges from a location that is closer to the observer than the crest of the previous wave.

As a result, each wave travels to the observer slightly faster than the one before it. As a result, the interval between successive wave crests arriving at the observer is shorter, increasing the frequency.

Learn more about Doppler effect here brainly.com/question/4052291

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The velocity of sound in air at STP (Standard Temperature and Pressure) is approximately 344 m/s. If the frequency of the sound

exis [7]

Answer:

0.066m

Explanation:

use the formula

velocity= frequency × wave length

344m/s = 5200Hz× wavelength

wavelength = 344m/s/5200Hz

wavelength = 0.066m(to 2 sig fig)

5 0

3 years ago

List the two types of mechanical waves and define them.

Liula [17]

The two types of mechanical waves are longitudinal waves, and transversal waves.

7 0

3 years ago

This time particle A starts from rest and accelerates to the right at 65.5 cm/s

FrozenT [24]

Answer:

t = 4 s

Explanation:

As we know that the particle A starts from Rest with constant acceleration

So the distance moved by the particle in given time "t"

$d = v_i t + \frac{1}{2}at^2$

$d = 0 + \frac{1}{2}(65.5)t^2$

$d_1 = 32.75 t^2 cm$

Now we know that B moves with constant speed so in the same time B will move to another distance

$d_2 = 44 \times t$

now we know that B is already 349 cm down the track

so if A and B will meet after time "t"

then in that case

$d_1 = 349 + d_2$

$32.75 t^2 = 349 + 44 t$

on solving above kinematics equation we have

$t = 4 s$

4 0

3 years ago

Calculate the work done (in J) by a 90.0 kg man who pushes a crate 4.25 m up along a ramp that makes an angle of 20.0° with the

Mrrafil [7]

Answer:

W = 3.4x0³ J.

Explanation:

The work done by the man is given by the following equation:

$W = F_{t}\cdot d$ (1)

<em>where W: is the work, Ft is the total force and d: is the displacement = 4.25 m.</em>

We need to find first the total force Ft, which is:

$Ft = Fm + W$

<em>where Fm: is the force exerted by the man = 535 N, W: is the weight = m*g*sin(θ), m: is the mass of the man, g: is the gravitational acceleration = 9.81 m/s², and θ: is the angle = 20.0°. </em>

$F_{t} = Fm + W = 500 N + 90.0 kg*9.81 m/s^{2} * sin(20.0) = 802.0 N$

Hence, the work is:

$W = 802.0 N \cdot 4.25 m = 3.4 \cdot 10 ^{3} J$

Therefore, the work done by the man is 3.4x10³ J.

I hope it helps you!

8 0

3 years ago

I need help plz and thank you. This is past due and I will mark brainiest

Zielflug [23.3K]

Answer:

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Explanation:

4 0

3 years ago

Read 2 more answers