I'd go for b) v squared.
Wind is air in motion. So, it has kinetic energy. For a given mass of air at a certain speed, the kinetic energy would be (1/2)mv^2.
Since everything else in the chain seems to be proportional, then it's the v^2 bit that seems to be important. Hence the answer I post here.
A measure of the quantity of matter is called mass. D.
This is how much of matter is contained in an object. It is different from weight, which is the pull of gravity on an object.
The difference between the parts of the plot with positive slope and the parts with negative slope can be found below.
<h3>What is a slope?</h3>
A slope in a graph is the ratio of the vertical and horizontal distances between two points on a line. Slope shows both steepness and direction of values.
A slope can either be positive or negative depending on the relationship between the variables being plotted.
A positive slope means that the variable are directly related while the negative slope means that two variables are negatively related.
A positive slope further means that the line moves upward when going from left to right on the graph while with the negative slope, the line moves down when going from left to right.
Learn more about slope at: brainly.com/question/2491620
#SPJ1
Answer:
v₀ₓ = 63.5 m/s
v₀y = 54.2 m/s
Explanation:
First we find the net launch velocity of projectile. For that purpose, we use the formula of kinetic energy:
K.E = (0.5)(mv₀²)
where,
K.E = initial kinetic energy of projectile = 1430 J
m = mass of projectile = 0.41 kg
v₀ = launch velocity of projectile = ?
Therefore,
1430 J = (0.5)(0.41)v₀²
v₀ = √(6975.6 m²/s²)
v₀ = 83.5 m/s
Now, we find the launching angle, by using formula for maximum height of projectile:
h = v₀² Sin²θ/2g
where,
h = height of projectile = 150 m
g = 9.8 m/s²
θ = launch angle
Therefore,
150 m = (83.5 m/s)²Sin²θ/(2)(9.8 m/s²)
Sin θ = √(0.4216)
θ = Sin⁻¹ (0.6493)
θ = 40.5°
Now, we find the components of launch velocity:
x- component = v₀ₓ = v₀Cosθ = (83.5 m/s) Cos(40.5°)
<u>v₀ₓ = 63.5 m/s</u>
y- component = v₀y = v₀Sinθ = (83.5 m/s) Sin(40.5°)
<u>v₀y = 54.2 m/s</u>