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2 years ago

11

Thanks + BRAINLIST Please need correct answer asappp

1 answer:

nirvana33 [79]2 years ago

6 0

Answer:

Standing waves can be thought of as a sin wave and a cos wave overlapping each other. They go in different direction hence C is correct
Wave interference can be thought of as the opposite of destructive ---> constructive anda hencd meet and interact on the same medium such that answer B is correct

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As a woman walks, her entire weight is momentarily placed on one heel of her high-heeled shoes. Calculate the pressure exerted o

Inessa05 [86]

Answer:4.003 MPa

Explanation:

Given

Area of heel $A=1.64 cm^2\approx 1.64\times 10^{-4} m^2$

Mass of woman $m= 67 kg$

Pressure is defined as Force applied in over an area such that it is perpendicular to it i.e.

$Pressure=\frac{Force}{Area}$

$P=\frac{F}{A}$

$P=\frac{mg}{A}$

$P=\frac{67\times 9.8}{1.64\times 10^{-4}}$

$P=400.365\times 10^{4} Pa$

$P=4.003 MPa$

7 0

3 years ago

How many atoms of hydrogen are there in one molecule of ammonium phosphate, if the chemical formula is (NH4)3PO4?

joja [24]

Answer:

The answer is D.

Explanation:

There are 12 atoms of H present in ammonium phosphate (NH4)3PO4.

6 0

2 years ago

A net force applied to a 15.0 kg box produced an acceleration of 4.2 m/s2. If the same net force was applied to a 10 kg box, wha

igor_vitrenko [27]

Answer:

$6.3\ m/s^2$

Explanation:

Given that,

If the mass of a body is 15 kg and produced an 4.2 m/s², we need to find the acceleration if the mass is 10 kg and the same force is applied.

Force is given by :

F = ma

Since force is same

$m_1a_1=m_2a_2\\\\a_2=\dfrac{m_1a_1}{m_2}\\\\a_2=\dfrac{15\times 4.2}{10}\\\\a=6.3\ m/s^2$

So, if the mass is 10 kg, acceleration is $6.3\ m/s^2$

8 0

2 years ago

A shell is fired from the ground with an initial speed of 1.57 ✕ 103 m/s at an initial angle of 38° to the horizontal. (a) Negle

Simora [160]

Answer:

a) Shell's horizontal range = 243798.70 m

b) The amount of time the shell is in motion = 197.06 s

Explanation:

Consider the vertical motion of projectile,

We have equation of motion s = ut + 0.5 at²

Initial velocity, u = 1.57 x 10³ sin 38 = 966.59 m/s

Acceleration, a = -9.81 m/s²

Displacement is zero when the shell reaches back to ground, s = 0 m

Time, t =?

Substituting,

s = ut + 0.5 at²

0 = 966.59 x t + 0.5 x (-9.81) x t²

t = 197.06 seconds

b) The amount of time the shell is in motion = 197.06 s

a) Consider the horizontal motion of shell

We have equation of motion s = ut + 0.5 at²

Initial velocity, u = 1.57 x 10³ cos 38 = 1237.18 m/s

Acceleration, a = 0 m/s²

Displacement, s = ?

Time, t = 197.06 s

Substituting,

s = ut + 0.5 at²

s = 1237.18 x 197.06 + 0.5 x 0 x 197.06²

s =243798.70 m

Shell's horizontal range = 243798.70 m

8 0

2 years ago

Need help quick, What is the average density of a neutron star in (LBS- Pounds) Will give brainliest! in tons if it makes it eas

Rzqust [24]

Answer:

It's about 220,462,262,184,877,568 pounds

Explanation:

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5 0

3 years ago