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3 years ago

How would you generate awareness in your school/society regarding renewable energy and its importances?

Physics

1 answer:

HACTEHA [7]3 years ago

6 0

Explanation:

<h3>Using clean, renewable energy is </h3><h3>one of the most important actions </h3><h3>you can take to reduce your impact </h3><h3>on the environment. Electricity production is our #1 source of greenhouse gases, more than all of our </h3><h3>driving and flying combined, and clean </h3><h3>energy also reduces harmful smog, toxic buildups in our air and water, and the </h3><h3>impacts caused by coal mining and gas extraction. But replacing our fossil-fuel infrastructure will take</h3><h3> time—and strong, consistent support from both state and federal </h3><h3>mandates to build renewable energy generation and demand for clean energy from consumers and businesses.</h3>

<h3>Why Renewable Energy? </h3>

<h3>Electricity generation is the second leading cause of industrial air</h3><h3> pollution in the U.S. </h3><h3>Most of our electricity comes from coal, nuclear, and other non-renewable power plants. Producing energy from these </h3><h3>resources takes a severe toll on our environment, polluting our air, land, and</h3><h3> water.</h3>

<h3>Renewable energy sources can be used to produce electricity with</h3><h3> fewer environmental impacts. It is possible to make electricity from renewable energy sources without producing carbon dioxide (CO2), the leading cause of global climate change.</h3>

<h3>Renewables Benefit the Economy</h3><h3>Renewable energy provides reliable power supplies and fuel diversification, which enhance energy security, </h3><h3>lower risk of fuel spills, and reduce</h3><h3> the need for imported fuels. Renewable energy also helps conserve the nation's natural resources.</h3>

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A traves de una manguera de 1 in de diámetro fluye gasolina con una velocidad media de 5ft/s ¿cuál es el gasto?

jonny [76]

Answer:

El gasto de gasto es de aproximadamente 0.0273 pies cúbicos por segundo.

Explanation:

El gasto es el flujo volumétrico de gasolina ( $Q$ ), medido en pies cúbicos por segundo, que sale de la manguera. Asumiendo que la velocidad de salida es constante, tenemos que el gasto a través de la manguera es:

$Q = \frac{\pi}{4}\cdot D^{2}\cdot v$ (1)

Donde:

$D$ - Diámetro de la manguera, medido en pies.

$v$ - Velocidad medida de salida, medida en pies por segundo.

Si sabemos que $D = \frac{1}{12}\,ft$ y $v = 5\,\frac{ft}{s }$ , entonces el gasto de gasolina es:

$Q = \frac{\pi}{4}\cdot \left(\frac{1}{12}\,ft \right)^{2} \cdot \left(5\,\frac{ft}{s} \right)$

$Q \approx 0.0273\,\frac{ft^{3}}{s}$

El gasto de gasto es de aproximadamente 0.0273 pies cúbicos por segundo.

6 0

3 years ago

The cavity within a copper [β = 51 × 10-6 (C°)-1] sphere has a volume of 1.180 × 10-3 m3. Into this cavity is placed 1.100 × 10-

nikdorinn [45]

Answer:

The answer is " $60.74^{\circ}$ ".

Explanation:

Cavity and benzene should be extended in equal quantities.

$\to 1.18 \times 10^{-3}\times (1+ \Delta T \times 0.000051) = 1.1\times 10^{-3} \times (1+ \Delta T \times 0.00124)\\\\\to (\frac{1.18}{1.1})\times (1+ \Delta T \times 0.000051) = 1+ \Delta T \times 0.00124\\\\ \to 1.072\times (1+ \Delta T \times 0.000051) = 1+ \Delta T \times 0.00124\\\\ \to 1.072+ \Delta T \times 0.000054672 = 1+ \Delta T \times 0.00124\\\\ \to 1.072+ \Delta T \times 0.000054672 - 1- \Delta T \times 0.00124=0\\\\$

$\to 0.072+ \Delta T \times 0.000054672 - \Delta T \times 0.00124=0\\\\ \to 0.072+ \Delta T ( 0.000054672 -0.00124)=0\\\\ \to \Delta T ( 0.000054672 -0.00124)= -0.072\\\\ \to \Delta T = -\frac{0.072}{( 0.000054672 -0.00124)}\\\\ \to \Delta T = -\frac{0.072}{-0.001185328 }\\$

$\to \Delta T = \frac{0.072}{0.001185328 }\\\\ \to \Delta T = 60.74^{\circ}\\$

5 0

3 years ago

A 10 m long clothesline is strung so that it is perfectly horizontal. when a shirt is hung in the exact center the line sags to

Leto [7]

Answer:

x = 0.0873 m

Explanation:

given,

length of clothesline = 10 m

the line sags to create an angle that is 1 degree below the horizontal on each end.

As mass is hang at the center the angle made let the deflection be 'x'

as the shirt is hang at the center distance will be equal to 5 m.

now

$tan \theta = \dfrac{d_e}{d}$

$tan \theta = \dfrac{x}{5}$

$tan 1^0 = \dfrac{W}{5}$

$W = 5 \times 0.0175$

x = 0.0873 m

Hence, the cloth line will be x = 0.0873 m from the original length of the clothesline.

3 0

3 years ago

The conversion of potential energy in coal into the kinetic energy that heats steam is an expression of: Answer the first law of

erastova [34]

Let me think about this........ correct me if I am wrong....... Laws of thermodynamics 1) Energy cannot be created nor destroyed. It is transferred. 2) All spontaneous reactions will increased the entropy of the universe (More disorder) 3) The entropy of the crystal lattice structure at 0 K is zero PE(coal) --> Steam(K.E) ................ This will increase entropy and also conversion of energy. So BOTH LAWS is my final answer. Wait...... I would like to use a lifelines...... I want to phone my Physical chem professor. *Ring Ring.........* Me: Hello, I wanted to make sure if I got the correct answer. Chem prof: You dont need my help, since you got the right answer. Me: WOOT!!!!!!!

7 0

3 years ago

An object of mass m is traveling around a circle of radius v. What happens to the centripetal force if the radius is cut in half

german

Answer:

Centripetal force doubles

Explanation:

Since centripetal force is given by

$F=\frac {mv^{2}}{r}$

Where F is the centripetal force, m is the mass, v is the centripetal velocity and r is circle radius.

When the radius is reduced to half then the centripetal force will be

$F=\frac {mv^{2}}{0.5r}=\frac {2mv^{2}}{r}$

Evidently, the centripetal force is doubled compared to the initial.

Note that while the question gives letter v for radius, I used v for velocity and r for radius since these are the standard letters for abbreviating formula of centripetal force.

7 0

3 years ago