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trasher [3.6K]
1 year ago
8

A mathematical equation useful for dilution calculations is Mdil × Vdil = Mconc × Vconc (a) What does each symbol mean, and why

does the equation work?
Chemistry
1 answer:
anygoal [31]1 year ago
7 0

Dilution is the process of “lowering the concentration of a solute in a solution by simply adding more solvent to the solution, such as water.” Diluting a solution entails adding more solvent without adding more solute.

<h3>How do you do dilution in math?</h3>

The number of dilutions is equal to the number of times the dilution factor will be multiplied by itself to equal the starting concentration divided by the final concentration. So with a dilution factor of 10, 10 to the X power is equal to the starting concentration divided by the final concentration.

<h3>How do you find the dilution of a solution?</h3>

You can solve for the concentration or volume of the concentrated or dilute solution using the equation: M1V1 = M2V2, where M1 is the concentration in molarity (moles/Liters) of the concentrated solution, V2 is the volume of the concentrated solution, M2 is the concentration in molarity of the dilute solution.

Learn more about dilution here:

<h3>brainly.com/question/1553819</h3><h3 /><h3>#SPJ4</h3>

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assume that a water balloon has the same number of water molecules as a helium balloon has helium atoms. If the mass of the wate
Aloiza [94]

Answer : The mass of the water molecule is 4.5 times greater than the mass of the helium atom.

Explanation :

Assumption : The number of water molecules is equal to the number of helium atoms

Given : The mass of water = 4.5 × The mass of helium     ........(1)

The mass of Water = Mass of 1 water molecule × Number of water molecule

The mass of Helium = Mass of 1 helium atom × Number of helium atom

Now these two masses expression put in the equation (1), we get

Mass of 1 water molecule × Number of water molecule = 4.5 × Mass of 1 helium atom × Number of helium atom

As per assumption, the number of water molecules is equal to the number of helium atoms. The relation between the mass of water molecule and the mass of helium atom is,

Mass of water molecule = 4.5 × Mass of helium atom

Therefore, the mass of the water molecule is 4.5 times greater than the mass of the helium atom.

3 0
3 years ago
imagine that you're able to fully dissolve a powered substance and water what can be said about this creation
Softa [21]
We can say that the water is the solvent, and the powder is the solute. This is also a solution altogether. 

Explanation:- A solute is the thing being dissolved into the solvent. While the solvent is what when the solute is being dissolved in. Together, they make a solution. 
8 0
3 years ago
Mass = 35g Volume = 7cm3 What is the Density?​
olga_2 [115]

Answer:

5 g/cm^3

Explanation:√3V=1.91293cm

7 0
3 years ago
stbank, Question 075 Get help answering Molecular Drawing questions. Compound A, C6H12 reacts with HBr/ROOR to give compound B,
Law Incorporation [45]

Answer:

Explanation:

In this case we want to know the structures of A (C6H12), B (C6H13Br) and C (C6H14).

A and C reacts with two differents reagents and conditions, however both of them gives the same product.

Let's analyze each reaction.

First, C6H12 has the general formula of an alkene or cycloalkane. However, when we look at the reagents, which are HBr in ROOR, and the final product, we can see that this is an adition reaction where the H and Br were added to a molecule, therefore we can conclude that the initial reactant is an alkene. Now, what happens next? A is reacting with HBr. In general terms when we have an adition of a molecule to a reactant like HBr (Adding electrophyle and nucleophyle) this kind of reactions follows the markonikov's rule that states that the hydrogen will go to the carbon with more hydrogens, and the nucleophyle will go to the carbon with less hydrogen (Atom that can be stabilized with charge). But in this case, we have something else and is the use of the ROOR, this is a peroxide so, instead of follow the markonikov rule, it will do the opposite, the hydrogen to the more substituted carbon and the bromine to the carbon with more hydrogens. This is called the antimarkonikov rule. Picture attached show the possible structure for A. The alkene would have to be the 1-hexene.

Now in the second case we have C, reacting with bromine in light to give also B. C has the formula C6H14 which is the formula for an alkane and once again we are having an adition reaction. In this case, conditions are given to do an adition reaction in an alkane. bromine in presence of light promoves the adition of the bromine to the molecule of alkane. In this case it can go to the carbon with more hydrogen or less hydrogens, but it will prefer the carbon with more hydrogens. In this case would be the terminal hydrogens of the molecules. In this case, it will form product B again. the alkane here would be the hexane. See picture for structures.

8 0
3 years ago
Are metallic bonds are found in compounds
Ratling [72]

Answer:

Explanation:

Yes :)

Mark brainliest please

5 0
3 years ago
Read 2 more answers
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