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mash [69]
3 years ago
8

As an object falls freely near the earths surface , the loss in gravitational potential energy of the object is equal to its wha

t
Chemistry
2 answers:
Romashka [77]3 years ago
6 0

Answer:

Therefore the loss (transfer) of this potential energy is equal to the increase in kinetic energy

Explanation:

First remember that energy is not destroyed, it only transpires

There are different types of energy, an example of different types of energy is the heat energy (the one that is transferred from an object that is hotter to another, or also by friction), the gravitational potential energy (increases when the height of an object increases with respect to the zero point) another example would be the kinetic energy (increases with increasing the speed of an object)

When object "loses" energy is really transforming into another type of energy

While an object falls and loses its potential energy (it loses height) it increases its speed (it falls faster and faster), as its speed increases the kinetic energy increases

Therefore the loss (transfer) of this potential energy is equal to the increase in kinetic energy

Nitella [24]3 years ago
4 0
Increase in kinetic energy as well as energy loss to the surroundings in the form of heat ( negligible)
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What mass of NaC6H5COO should be added to 1.5 L of 0.40 M C6H5COOH solution at 25 °C to produce a solution with a pH of 3.87 giv
statuscvo [17]

Answer:

41 g

Explanation:

We have a buffer formed by a weak acid (C₆H₅COOH) and its conjugate base (C₆H₅COO⁻ coming from NaC₆H₅COO). We can find the concentration of C₆H₅COO⁻ (and therefore of NaC₆H₅COO) using the Henderson-Hasselbach equation.

pH = pKa + log [C₆H₅COO⁻]/[C₆H₅COOH]

pH - pKa = log [C₆H₅COO⁻] - log [C₆H₅COOH]

log [C₆H₅COO⁻] = pH - pKa + log [C₆H₅COOH]

log [C₆H₅COO⁻] = 3.87 - (-log 6.5 × 10⁻⁵) + log 0.40

[C₆H₅COO⁻] = [NaC₆H₅COO] = 0.19 M

We can find the mass of NaC₆H₅COO using the following expression.

M = mass NaC₆H₅COO / molar mass NaC₆H₅COO × liters of solution

mass NaC₆H₅COO = M × molar mass NaC₆H₅COO × liters of solution

mass NaC₆H₅COO = 0.19 mol/L × 144.1032 g/mol × 1.5 L

mass NaC₆H₅COO = 41 g

7 0
3 years ago
What is the maximum mass of ethyl alcohol you could boil with 1000 j of heat, starting from 22 ∘c?
kramer

solution:

1000 = m*2400*(78-22) + m*8.79*10^5

1000= 134400m + 879000m

1000= 1030200m

m = 1000/1013400

m= 1013.4 grams

the final answer is 0.9706 grams


5 0
3 years ago
What is the molar mass of a gas if 0.102 g of the gas occupies 0.070 L at STP? a. 32.6g / mol b. 28.2 g/mol c. 40.0g / mol d. 47
alexgriva [62]

Answer:

A. 32.6 g/mol

Explanation:

First convert the volume of gas to moles using the ratio 1 mol / 22.4 L at STP.

0.070 L • (1 mol / 22.4 L) = 0.00313 mol

Now divide the grams of gas by the moles of gas:

0.102 g / 0.00313 mol = 32.6 g/mol

8 0
3 years ago
How much energy is required to melt 35.4 g of gold?
kap26 [50]

Answer:

To determine the amount of heat the gold has absorbed to melt, we simply multiply the mass of the block of ice to the heat of fusion of water which is given above. We calculate as follows:

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4 0
3 years ago
Is fluber liquid or solid
Gennadij [26K]
Nor liquid or solid since flubber is like oobleck, it is a non newtonian object.
3 0
3 years ago
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