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mash [69]
2 years ago
8

As an object falls freely near the earths surface , the loss in gravitational potential energy of the object is equal to its wha

t
Chemistry
2 answers:
Romashka [77]2 years ago
6 0

Answer:

Therefore the loss (transfer) of this potential energy is equal to the increase in kinetic energy

Explanation:

First remember that energy is not destroyed, it only transpires

There are different types of energy, an example of different types of energy is the heat energy (the one that is transferred from an object that is hotter to another, or also by friction), the gravitational potential energy (increases when the height of an object increases with respect to the zero point) another example would be the kinetic energy (increases with increasing the speed of an object)

When object "loses" energy is really transforming into another type of energy

While an object falls and loses its potential energy (it loses height) it increases its speed (it falls faster and faster), as its speed increases the kinetic energy increases

Therefore the loss (transfer) of this potential energy is equal to the increase in kinetic energy

Nitella [24]2 years ago
4 0
Increase in kinetic energy as well as energy loss to the surroundings in the form of heat ( negligible)
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The most common cooling mechanism for cloud formation is ________.
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The answer is "Rising and expanding air or atmosphere cooling".
To form a cloud the air must be cooled to the temperature of dew point. when there is expansion of air, it cools to the dew point and thus the formation of cloud happens. This process is very common and used for the formation of clouds.
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Water at the bottom of a narrow metal tube is held at a constant temperature of 293 K. The total pressure of air (assumed dry) i
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1.595 x 10-7kmol/m2.s Explanation:

3 0
3 years ago
Using the following thermochemical equation, determine the amount of heat produced per kg of CO2 formed during the combustion of
Arisa [49]

Answer:  12033 kJ of heat produced per kg of CO_2 formed during the combustion of benzene

Explanation:

The balanced chemical equation for combustion of benzene is :

2C_6H_6(l)+15O_2(g)\rightarrow 12CO_2(g)+6H_2O(g)  \Delta H°rxn = -6278 kJ

Exothermic reactions are defined as the reactions in which energy of the product is lesser than the energy of the reactants. The total energy is released in the form of heat and \Delta H for the reaction comes out to be negative.

\text{Moles of }CO_2=\frac{\text{given mass}}{\text{Molar Mass}}=\frac{1000g}{44g/mol}=23mol      (1kg=1000g)

According to stoichiometry :

12 moles of CO_2 on combustion produce heat = 6278 kJ

Thus 23 mole of CO_2 on combustion produce heat =\frac{6278}{12}\times 23=12033kJ

Thus 12033 kJ of heat produced per kg of CO_2 formed during the combustion of benzene

5 0
2 years ago
Use the data given below to construct a Born-Haber cycle to determine the second ionization energy of Ca. Δ H°(kJ) Ca(s)→Ca(g) 1
Drupady [299]

Answer :  The value of second ionization energy of Ca is 1010 kJ.

Explanation :  

The formation of calcium oxide is,

Ca(s)+\frac{1}{2}O_2(g)\overset{\Delta H_f}\rightarrow CaO(s)

\Delta H_f^o = enthalpy of formation of calcium oxide = -635 kJ

The steps involved in the born-Haber cycle for the formation of CaO:

(1) Conversion of solid calcium into gaseous calcium atoms.

Ca(s)\overset{\Delta H_s}\rightarrow Ca(g)

\Delta H_s = sublimation energy of calcium = 193 kJ

(2) Conversion of gaseous calcium atoms into gaseous calcium ions.

Ca(g)\overset{\Delta H_I_1}\rightarrow Ca^{+1}(g)

\Delta H_I_1 = first ionization energy of calcium = 590 kJ

(3) Conversion of gaseous calcium ion into gaseous calcium ions.

Ca^{+1}(g)\overset{\Delta H_I_2}\rightarrow Ca^{+2}(g)

\Delta H_I_2 = second ionization energy of calcium = ?

(4) Conversion of molecular gaseous oxygen into gaseous oxygen atoms.

O_2(g)\overset{\Delta H_D}\rightarrow OI(g)

\frac{1}{2}O_2(g)\overset{\Delta H_D}\rightarrow O(g)

\Delta H_D = dissociation energy of oxygen = \frac{498}{2}=249kJ

(5) Conversion of gaseous oxygen atoms into gaseous oxygen ions.

O(g)\overset{\Delta H_E_1}\rightarrow O^-(g)

\Delta H_E_1 = first electron affinity energy of oxygen = -141 kJ

(6) Conversion of gaseous oxygen ion into gaseous oxygen ions.

O^-(g)\overset{\Delta H_E_2}\rightarrow O^{2-}(g)

\Delta H_E_2 = second electron affinity energy of oxygen = 878 kJ

(7) Conversion of gaseous cations and gaseous anion into solid calcium oxide.

Ca^{2+}(g)+O^{2-}(g)\overset{\Delta H_L}\rightarrow CaO(s)

\Delta H_L = lattice energy of calcium oxide = -3414 kJ

To calculate the overall energy from the born-Haber cycle, the equation used will be:

\Delta H_f^o=\Delta H_s+\Delta H_I_1+\Delta H_I_2+\Delta H_D+\Delta H_E_1+\Delta H_E_2+\Delta H_L

Now put all the given values in this equation, we get:

-635kJ=193kJ+590kJ+\Delta H_I_2+249kJ+(-141kJ)+878kJ+(-3414kJ)

\Delta H_I_2=1010kJ

Therefore, the value of second ionization energy of Ca is 1010 kJ.

6 0
2 years ago
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