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Nimfa-mama [501]
1 year ago
12

what salt is formed in the reaction of aluminum with hydrochloric acid? write the formula of the salt. formula:

Chemistry
1 answer:
Alenkasestr [34]1 year ago
3 0

Aluminum chloride is formed in the reaction of aluminum with hydrochloric acid. The formula of aluminum chloride is AlCl₃.

Aluminium chloride, additionally referred to as Aluminium trichloride, is an inorganic compound with the formula AlCl₃. It bureaucracy hexahydrate with the system [Al(H₂O)₆]Cl₃, containing six water molecules of hydration. Each are colourless crystals, however samples are regularly contaminated with iron(III) chloride, giving a yellow shade.

Aluminum Chloride is used to control immoderate sweating. This medicinal drug can be used for other purposes; ask your fitness care provider or pharmacist when you have questions.

Aluminum chloride is corrosive and nerve-racking to the eyes, skin, and mucous membranes. Can be dangerous if swallowed. Ingestion of big quantities may also motive phosphate deficiency. Aluminum chloride is a compound of aluminum and chloride it truly is widely utilized in petroleum refining and the producing of many products. similarly, antiperspirants and cosmetic astringents use this compound.

Learn more about aluminum chloride here:- brainly.com/question/6061451

#SPJ4

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6 0
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Read 2 more answers
Evaluate the exponential expression (−2)6.
Olegator [25]

A general exponential expression is something like:

A^n

This means that we need to multiply the number A by itself n times.

Using that we will get (-2)^6 = 64

With that definition, we can rewrite:

(-2)^6 = (-2)*(-2)*(-2)*(-2)*(-2)*(-2)

So we just need to solve the above expression.

Also, remember the rule of signs:

(-)*(-) = (+)

We will get:

(-2)*(-2)*(-2)*(-2)*(-2)*(-2) =  [(-2)*(-2)]*[(-2)*(-2)]*[(-2)*(-2)]

                                        =  4*4*4 = 16*4 = 64

Then we got:

(-2)^6 = 64

If you want to learn more, you can read:

brainly.com/question/17172630

6 0
3 years ago
Help!!!
kupik [55]

Answer:

1. 0.82 gram of Ag+

2. 4.79 g of Ag₂O₃S

Explanation:

From the given information:

Total amount of Ag₂O₃S = 2.24 grams

Atomic mass of Ag+ =107.86 g/mole

molar mass of Ag₂O₃S = 295.8  g/mole

∴

The mass of the Silver (Ag) in grams is:

= Total\ amount \ of \ Ag^+ \times \dfrac{107.86 \ g/mol}{295.8 \ g/mol}

=2.24 \times \dfrac{107.86 \ g/mol}{295.8 \ g/mol}

= 0.82 gram of Ag+

2.

Here, the total amount of Ag₂O₃S = unknown

Atomic mass of Ag+ = 107.86 g/mole

molar mass of Ag₂O₃S = 295.8 g/mole

amount of Ag+  = 1.75 g

∴

The mass of Ag₂O₃S = Total \ amount \ of \ Ag^+ \times \dfrac{295.8 \ g/mol}{107.86\ g/mol}

=1.75  \times  \dfrac{295.8 \ g/mol}{107.86\ g/mol}

= 4.79 g of Ag₂O₃S

4 0
3 years ago
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