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Ugo [173]
3 years ago
12

HELP QUICK: A pilot performs a vertical maneuver around a circle with a radius R. When the

Physics
1 answer:
DanielleElmas [232]3 years ago
5 0

Answer:

dswdkwqdtlwaFwa

Explanation:

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1. Two forces F~ 1 and F~ 2 are acting on a block of mass m=1.5 kg. The magnitude of force F~ 1 is 12N and it makes an angle of
VLD [36.1K]

Answer:

Normal force=7.48 N

Explanation:

N+F~1 sinθ-mg=0

=>N=1.5*9.8-12 sin37◦

=>N=14.7-7.22=7.48 N

6 0
3 years ago
You are on a boat which is crossing the prime meridian. the altitude of polaris is 50º.explain how you know the boat's location
Lerok [7]
The definition for the prime meridian is: The prime meridian with 0 degrees longitude runs through Greenwich. Polaris is the north star <span>at 50 degrees above the horizon, which means 50 degrees latitude. 
</span>If you observe Polaris  at 50 degrees of altitude, you are at latitude 50 North. You that's why you know that your boat's location is <span>50º north latitude and 0º longitude.</span>
7 0
3 years ago
To calculate the change in kinetic energy, you must know the force as a function of _______. the work done by the force causes t
trapecia [35]
Kinetic energy is a result of mass in motion at a certain velocity.
<span>1 Joule = 1 kg • (m/s)<span>2
</span></span>the force as a function of mass of the object.
4 0
3 years ago
A wave on the ocean surface with wavelength 44 m travels east at a speed of 18 m/s relative to the ocean floor. If, on this stre
inessss [21]

Answer:

A)t=<u>1.375s</u>

B)t=11s

Explanation:

for this problem we will assume that the east is positive while the west is negative, what we must do is find the relative speed between the wave and the powerboat, and then with the distance find the time for each case

ecuations

V=Vw-Vp  (1)

V= relative speed

Vw= speed of wave

Vp=Speesd

t=X/V(2)

t=time

x=distance=44m

A) the powerboat moves to west

V=18-(-14)=32m/s

t=44/32=<u>1.375s</u>

B)the powerboat moves to east

V=18-14=4

t=44/4=<u>11s</u>

3 0
3 years ago
A car is sitting motionless on top of a bridge. The bridge pushes up on the car with a force of 782 Newtons.
Evgesh-ka [11]

Answer: The car would move to the right with 150 n of force. the 150 n of force from friction and air resistance slows the car from moving to the right with 300 n of force.

Explanation:

3 0
2 years ago
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