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GrogVix [38]
3 years ago
9

Please need me know! Chem question

Chemistry
1 answer:
Inessa [10]3 years ago
5 0
90 degrees
As temperature increases, rate of reaction increases :)
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Which of the following gases would diffuse the fastest? <br> CH 4<br> CCl 4 <br> O 2<br> H 2
Sholpan [36]
H2 <span>because the smaller the gas molecule, the faster the diffusion. (the lightest molecule will diffuse the quickest)</span>
8 0
4 years ago
5 properties of acids
Dahasolnce [82]

Answer:

   Acids change the color of litmus from blue to red.

   They convert the color of Methyl Orange from Orange/Yellow to Pink.

   Acids turn the pink color of Phenolphthalein to colourless.

   Acids can conduct electricity.

   Some Acids are highly corrosive in nature which means that they corrode or rust metals.

Explanation:

hope this helped

ur boi johnny joestar.

8 0
3 years ago
Read 2 more answers
Density = 11g/cm3 volume = 2cm3 what is the mass
jolli1 [7]
<h2><u>Q</u><u>u</u><u>e</u><u>s</u><u>t</u><u>i</u><u>o</u><u>n</u>:-</h2>

Density = 11g/cm³, volume = 2cm³. What is the mass ?

<h2><u>S</u><u>o</u><u>l</u><u>u</u><u>t</u><u>i</u><u>o</u><u>n</u>:-</h2>

We know,

{ \boxed{\bf{\rm \red {Mass \: = \: Density \: × \: Volume}}}}

So, Mass = 11g/cm³ × 2cm³

Mass = 22 g

<h3>The mass is <u>2</u><u>2</u><u> </u><u>g</u>. [Answer]</h3>
3 0
3 years ago
The specific heats and densities of several materials are given below: Material Specific Heat (cal/g·°C) Density (g/cm3) Brick 0
abruzzese [7]

<u>Answer:</u> The change in temperature is 84.7°C

<u>Explanation:</u>

To calculate the change in temperature, we use the equation:

q=mc\Delta T

where,

q = heat absorbed = 1 kCal = 1000 Cal    (Conversion factor: 1 kCal = 1000 Cal)

m = mass of steel = 100 g

c = specific heat capacity of steel = 0.118 Cal/g.°C

\Delta T = change in temperature = ?

Putting values in above equation, we get:

1000cal=100g\times 0.118cal/g^oC\times \Delta T\\\\\Delta T=\frac{1000cal}{100g\times 0.118cal/g^oC}\\\\\Delta T=84.7^oC

Hence, the change in temperature is 84.7°C

5 0
3 years ago
For H 2 O, the H-O-H bond angle is 104.5 o and the measure dipole moment is 1.85 Debye. What is the magnitude of the O-H bond di
viva [34]

Answer:

Dipole moment of H₂O: 2.26 Debye

Bond angle in H₂S: 89.7°

Explanation:

The total dipole moment(μr) for H₂O can be calculated by the sum of the dipole moments of each bond of O-H. Because the dipole moment is a vector, the sum of these vectors can be calculated by the cosine law.

μr² = (μO-H)² + (μO-H)² + 2*(μO-H)*(μO-H)*cos(104.5°)

μr² = 1.85² + 1.85² + 2*1.85*1.85*cos(104.5°)

μr² = 3.4225 + 3.4225 + 6.845*(-0.2504)

μr² = 5.13115

μr = √5.13115

μr = 2.26 Debye.

For H₂S:

0.95² = 0.67² + 0.67² + 2*0.67*0.67*cosθ

0.9025 = 0.4489 + 0.4489 + 0.8978cosθ

0.8978cosθ = 0.0047

cosθ = 0.00523

θ = arcos0.00523

θ = 89.7°

6 0
3 years ago
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