IDensity is calculated by mass divided by volume. As you half the Hershey bar, mass and volume change by the same proportion. Therefore, density is the same.
This problem is asking to predict the pressure in the container at a temperature of 1,135 K with no apparent background; however, in similar problems we can be given a graph having the pressure on the y-axis and the temperature on the x-axis and a trendline such as on the attached file, which leads to a pressure of 21.2 atm by using the given equation and considering the following:
<h3>Graph analysis.</h3>
In chemistry, experiments can be studied, modelled and quantified by using graphs in which we have both a dependent and independent variable; the former on the y-axis and the latter on the x-axis.
In addition, when data is recorded and graphed, one can use different computational tools to obtain a trendline and thus, attempt to find either the dependent or independent value depending on the requirement.
In this case, since the provided trendline by the graph and the program it was put in is y = 0.017x+1.940, we understand y stands for pressure and x for temperature so that we can extrapolate this equation even beyond the plotted points, which is this case.
In such a way, we can plug in the given temperature to obtain the required pressure as shown below:
y = 0.017 ( 1,135 ) + 1.940
y = 21.2
Answer that is in atm according to the units on the y-axis:
Learn more about trendlines: brainly.com/question/13298479
Answer:
A ,B- false
C,D- true
Explanation:
Dipole forces always lead to stronger attraction and boiling points than dispersion forces. When linear molecules are involved, they often posses greater dipole forces and higher boiling points. Linear alkanes posses higher boiling points than branched alkanes.
Answer:
C. Graph C
Explanation:
We have a mixture of water and ice.
At 0 °C they are at equilibrium.
water-to-ice rate = ice-to-water rate
Next, we lower the temperature to -3 °C — just slightly below freezing.
The water will slowly turn to ice.
The water-to-ice rate will be slightly faster than the ice-to-water rate.
The purple bar will be slightly higher than the blue bar.
Graph C best represents the relative rates
A. is wrong. The ice-to-water rate is faster, so the water is melting. The temperature is slightly above freezing (say, 3 °C).
B. is wrong. The two rates are equal, so the temperature is 0 °C.
D. is wrong. The water-to-ice rate (freezing) is much greater than the ice-to-water rate, so the temperature is well below freezing( say, -10 °C).
D. The empirical formula and the molar mass