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Airida [17]
2 years ago
8

For the following reaction, Kc = 15 at 700 K. 2 NO(g) + Cl2(g) ⇄ 2 NOCl(g) If we have [NO] = 0.15 M, [Cl2] = 0.15 M, [NOCl] = 0.

40 M at 700 K, what will happen? Group of answer choices The equilibrium will not shift. The equilibrium will shift to the left, but will use up only part of the NOCl. The equilibrium will shift to the right, but will use up only part of the NO and Cl2. The equilibrium will shift to the right until all the reactants are used up. The equilibrium will shift to the left until all the NOCl is used up.
Chemistry
1 answer:
vovangra [49]2 years ago
6 0

Answer : The correct option is, The equilibrium will shift to the left until all the NOCl is used up.

Explanation :

Reaction quotient (Q) : It is defined as the measurement of the relative amounts of products and reactants present during a reaction at a particular time.

The given balanced chemical reaction is,

2NO(g)+Cl_2(g)\rightarrow 2NOCl(g)

The expression for reaction quotient will be :

Q=\frac{[NOCl]^2}{[NO]^2[Cl_2]}

In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.

Now put all the given values in this expression, we get

Q=\frac{(0.40)^2}{(0.15)^2(0.15)}=47.4

The given equilibrium constant value is, K=15

Equilibrium constant : It is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.

There are 3 conditions:

When Q>K that means product > reactant. So, the reaction is reactant favored.

When Q that means reactant > product. So, the reaction is product favored.

When Q=K that means product = reactant. So, the reaction is in equilibrium.

From the above we conclude that, the Q>K that means product > reactant. So, the reaction is reactant favored that means reaction must shift to the reactants to be in equilibrium or shift to the left side.

Hence, the correct option is, The equilibrium will shift to the left until all the NOCl is used up.

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Express the concentration of a 0.0320 M aqueous solution of fluoride, F−, in mass percentage and in parts per million (ppm). Ass
denis23 [38]

Answer:

607 ppm

Explanation:

In this case we can start with the <u>ppm formula</u>:

ppm=\frac{mg~of~solute}{Litters~of~solution}

If we have a solution of <u>0.0320 M</u>, we can say that in 1 L we have 0.032 mol of F^-, because the molarity formula is:

M=\frac{mol}{L}

In other words:

0.0320~M=\frac{mol}{1~L}

mol=0.032~M*1~L=0.032~mol

1~L~of~Solution=0.0320~mol~of~solute

If we use the <u>atomic mass</u> of F  (19 g/mol) we can convert from mol to g:

0.0320~mol~F^-\frac{19~g~F^-}{1~mol~F^-}~=~0.607~g

Now we can <u>convert from g to mg</u> (1 g= 1000 mg), so:

0.607~g\frac{1000~mg}{1~g}=607~mg

Finally we can <u>divide by 1 L</u> to find the ppm:

ppm=\frac{607~mg}{1~L}=~607~ppm

<u>We will have a concentration of 607 ppm.</u>

I hope it helps!

4 0
3 years ago
Stainless steel is an alloy of iron, chromium, nickel, and manganese metals. If a 2.000 g sample contains 10.0% nickel, what is
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Answer:

200 g

Explanation:

Stainless steel is an alloy of iron, chromium, nickel, and manganese metals. A 2.000 g sample contains 10.0% nickel (mass percent), that is, there are 10.0 g of nickel every 100 g of the sample. The mass of nickel in the sample is:

2.000 g sample × (10.0 g Nickel/100 g sample) = 200 g Nickel

There are 200 grams of Nickel in the 2.000 g-sample.

7 0
3 years ago
10 m3 of carbon dioxide is originally at a temperature of 50 °C and pressure of 10 kPa. Determine the new density and volume of
Dimas [21]

Answer : The new density and new volume of carbon dioxide gas is 0.2281 g/L and 7.2m^3 respectively.

Explanation :

First we have to calculate the new or final volume of carbon dioxide gas.

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 10 kPa

P_2 = final pressure of gas = 15 kPa

V_1 = initial volume of gas = 10m^3

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 50^oC=273+50=323K

T_2 = final temperature of gas = 75^oC=273+75=348K

Now put all the given values in the above equation, we get:

\frac{10kPa\times 10m^3}{323K}=\frac{15kPa\times V_2}{348K}

V_2=7.2m^3

The new volume of carbon dioxide gas is 7.2m^3

Now we have to calculate the new density of carbon dioxide gas.

PV=nRT\\\\PV=\frac{m}{M}RT\\\\P=\frac{m}{V}\frac{RT}{M}\\\\P=\rho \frac{RT}{M}\\\\\rho=\frac{PM}{RT}

Formula for new density will be:

\rho_2=\frac{P_2M}{RT_2}

where,

P_2 = new pressure of gas = 15 kPa

T_2 = new temperature of gas = 75^oC=273+75=348K

M = molar mass of carbon dioxide gas = 44 g/mole

R = gas constant = 8.314 L.kPa/mol.K

\rho = new density

Now put all the given values in the above equation, we get:

\rho_2=\frac{(15kPa)\times (44g/mole)}{(8.314L.kPa/mol.K)\times (348K)}

\rho_2=0.2281g/L

The new density of carbon dioxide gas is 0.2281 g/L

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When cells or organisms maintain a stable internal state in a changing environment is called?
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erastova [34]

Explanation:

13 are the number of atoms

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