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leonid [27]
2 years ago
4

When a contracting hot ball of gas spins into a disk shape, it cools faster due to?

Chemistry
1 answer:
Anit [1.1K]2 years ago
3 0

Heat transfer is the gain or loss of heat by an object by heat conduction. The hot gas in disk shape cools faster because of increased surface area. Thus, option d is correct.

<h3>What is heat conduction?</h3>

Heat conduction is the thermal transportation of the heat from one substance to another by the virtue of the collision and the kinetic energy possessed by the particles of matter.

The rate of heat conduction has been directly proportional to the surface area. A contracting hot ball has a small area, whereas, a disk has a greater surface area and will cool faster.

Therefore, option d. the increased surface area cools faster.

Learn more about heat conduction, here:

brainly.com/question/9461731

#SPJ4

Your question is incomplete, but most probably your full question was, When a contracting hot ball of gas spins into a disk shape, it cools faster due to?

  • eddy currents
  • increased convection currents
  • increased radiation transfer
  • increased surface area
  • decreased insulation
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How many moles of hydrogen are in the sample?<br> Round your answer to 4 significant digits.
finlep [7]

Answer:

1.56 mol H₂

Explanation:

Mg₃(Si₂O₅)₂(OH)₂

<em>There are 4 Si moles per Mg₃(Si₂O₅)₂(OH)₂ mol</em>. With that in mind we can <u>calculate how many Mg₃(Si₂O₅)₂(OH)₂ moles are there in the sample</u>, using the <em>given number of silicon moles</em>:

  • 3.120 mol Si * \frac{1molMg_3(Si_2O_5)_2(OH)_2}{4molSi} = 0.78 mol Mg₃(Si₂O₅)₂(OH)₂

Then we can <u>convert Mg₃(Si₂O₅)₂(OH)₂ moles into hydrogen moles</u>, keeping in mind that <em>there are 2 hydrogen moles per Mg₃(Si₂O₅)₂(OH)₂ mol</em>:

  • 0.78 mol Mg₃(Si₂O₅)₂(OH)₂ * 2 = 1.56 mol H₂
8 0
3 years ago
What is the idea behid boyles law​
zavuch27 [327]

Answer:

Explanation:

For a fixed mass of an ideal gas kept at a fixed temperature, pressure and volume are inversely proportional. Or Boyle's law is a gas law, stating that the pressure and volume of a gas have an inverse relationship. If volume increases, then pressure decreases and vice versa, when the temperature is held constant.

3 0
2 years ago
Plz help for chemistry quiz I’ll mark brainliest
zvonat [6]

Answer: All of these answers are sorrect

ExplanationA scientist does all of these things while operforming a experiment

4 0
3 years ago
A 35.0-ml sample of 0.20 m lioh is titrated with 0.25 m hcl. What is the ph of the solution after 23.0 ml of hcl have been added
kiruha [24]
<h3><u>Answer;</u></h3>

pH = 12.33

<h3><u>Explanation;</u></h3>

The equation of reaction is :

LiOH(aq) + HCl(aq) --> LiCl(aq) + H2O(l)

Reactants left after the titrant is added;

Total Moles LiOH;

= 0.035L LiOH × (0.2moles/L)

= 0.007moles of LiOH

Moles of HCl;

= 0.023L HCl × (0.25moles/L)

= 0.00575moles HCl is the limiting reagent

Reacting amount of moles of LiOH;

= 0.0575 moles HCl *(1mole LiOH/1moles HCl)

=0.00575 moles LiOH (reacted)

Moles of LiOH left;

= 0.007moles total - 0.00575moles that react

= .00125 moles of LiOH (left)

LiOH is a strong base, which means that it ionizes completely.  

0.00125moles LiOH *(moles/0.058L) = 0.02155M of LiOH

LiOH(aq) --> Li+(aq) + OH-(aq)

[LiOH] = [OH-] = 0.02155 M

pOH = -log[OH-]

pOH = -log(0.02155)

pOH= 1.67

pH = 14 - pOH

pH = 14 - 1.67

pH = 12.33

7 0
3 years ago
Covalent bonds can occur where atoms share one or more pairs of electrons. Which of the following would form a double covalent b
mojhsa [17]

Answer:

The answer to your question is: CO2

Explanation:

The information given is correct, Covalent bonds occur when atoms share one or more pairs of electrons, but also, covalent bonds occur with nonmetals, then,

a.NaCl     This elements form an ionic bond, so this option is incorrect.

b.Cl2      Here there are two non metals  but the form one single covalent bond, so this option is incorrect.

c.CO2  Carbon dioxide forms 2 double covalent bonds.

d.NH3 ammonium only forms single covalent bonds

6 0
3 years ago
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