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2 years ago

An object that is dropped from a height H falls with a constant acceleration of g. The final

Physics

1 answer:

Crank2 years ago

3 0

The height has to change by a factor of 1.

<h3>What is the height?</h3>

We can obtain the height from which the object falls using the equations of kinematics under gravity. We can see that the object was dropped from a height thus u = 0 m/s.

We can the write;

v= √2gh

h1 = v^2/2g

When the final velocity is doubled, we have;

2v= √2gh

h2 =4v^2/2g

h2 = 2v^2/g

The height changes by;

2v^2/g - v^2/2g = v^2/g

Thus the height has to change by a factor of 1.

Learn more about height of an object:brainly.com/question/14451550

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